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3 years ago

Classify the following as an element, compound, homogeneous mixture, or heterogeneous mixture: iron (Fe)

Chemistry

1 answer:

Sunny_sXe [5.5K]3 years ago

7 0

Answer:

A. Element

Explanation:

Iron (Fe), chemical element and one of the transition elements, the most-used and cheapest metal.

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students used a balance and a graduated cylinder to collect the data shown in table 7. calculate the density of the sample. if t

Licemer1 [7]

Answer:

Percentage error = 1.88 %

Solution:

Data Given:

Mass of Sample = 20.46 g

Volume of Sample = 43.0 mL - 40.0 mL = 3.0 mL

Formula Used:

Density = Mass / Volume

Putting values,

Density = 20.46 g / 3.0 mL

Density = 6.82 g.mL⁻¹

Percentage Error:

Experimental Value = 6.82 g.mL⁻¹

Accepted Value = 6.95 g.mL⁻¹

= 6.82 g.mL⁻¹ / 6.95 g.mL⁻¹ × 100 = 98.12 %

Percentage Error = 100 % - 98.12 %

Percentage error = 1.88 %

3 0

2 years ago

Plz help :(

ziro4ka [17]

<h2>Answer:0.5 moles,1 mole</h2>

Explanation:

$Sr(NO_{3})_{2}$ is readily soluble in water.

$Sr(NO_{3})_{2}$ dissolves in water to give $Sr^{2+}$ ions and $NO_{3}^{-}$ ions.

The reaction is

$Sr(NO_{3})_{2}$ → $Sr^{2+}$ $+2NO_{3}^{-}$

So, $1$ mole of $Sr(NO_{3})_{2}$ gives $1$ mole of $Sr^{2+}$ and $2$ moles of $NO_{3}^{-}$ .

So, $0.5$ moles of $Sr(NO_{3})_{2}$ gives $0.5$ moles of $Sr^{2+}$ and $1$ mole of $NO_{3}^{-}$ .

5 0

3 years ago

What happens when magnesium reacts with dilute acid?

iogann1982 [59]

The magnesium dissolves to form magnesium chloride and hydrogen gas is released.

Mg + 2HCl -----> MgCl2 + H2(g).

5 0

2 years ago

I need to know the following above

arsen [322]

3Zn + 8HNO3 ---> 3Zn(NO3)2 + 4H2O + 2NO IF IT IS COLD AND DILUT NITRIC ACID .

IF IT IS HOT AND CONCENTRATED THEN:

Zn+ 4HNO3 ---> Zn(NO3)2 +2H2O +2NO2

6 0

2 years ago

A pharmacist wishes to strengthen a mixture from 10%alcohol to 30% alcohol. How much pure alcohol should be added to 7 liters of

Tomtit [17]

Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

$n_{old}=7$ litres
$n_{new}=7+x$ litres

Also the quantity of alcohol is given as

$q_{old}=10 \% \, of \, 7 \, litres =0.7$

$q_{added}=x$

$q_{new}= 30 \% \,of \,new\, quantity = 0.3(7+x)$

Now the equation is as

$q_{old}+q_{added}=q_{new}\\0.7+x=0.3(7+x)\\0.7+x=2.1+0.3x\\x-0.3x=2.1-0.7\\0.7x=1.4\\x=2 \, litres$

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

8 0

3 years ago