Answer:
Acceleration= final velocity - initial velocity / time
= (15 - 0)/ 5
= 3 m/s^2
Force = mass X acceleration
= 2 X 10^3 X 3
= 6 X 10^3 N
Answer:
1.) Fan Speed was manipulated
2.) The acceleration was measured
Explanation:
We will use the formula p = mgh
p is potential energy.
m is mass of object in kg
g is acceleration due to gravity (9.8m/s²)
h is height of the objects displacement in meters.
p = mgh → mgh = p → h = p / mg
p is 14000j, m is 40kg and g is 9.8 m/s²
h = 14000 / 40 × 9.8 → h = 1400 / 392 → h = 35.7
Therefore , the cannonball was 35.7 meters high .
Answer:
A) 8π ft²/ft
B) 24π ft²/ft
C) 48π ft²/ft
Explanation:
Surface area of the spherical balloon is not clear here but it is supposed to be;
S = 4πr²
where:
r is the radius of the spherical balloon
So thus, the rate of change of the surface area of the spherical balloon by its radius will be:
dS/dr = 8πr
A) at r = 1ft;
dS/dr = 8 × π × 1
dS/dr = 8π ft²/ft
B) at r = 3 ft;
dS/dr = 8 × π × 3
dS/dr = 24π ft²/ft
C) at r = 6ft;
dS/dr = 8 × π × 6
dS/dr = 48π ft²/ft
