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swat32
3 years ago
8

A resistor and a capacitor are connected in series to an ideal battery of constant terminal voltage. At the moment contact is ma

de with the battery, the voltage across the resistor is
Physics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

At the moment contact is made with the battery, the voltage across the resistor is equal to the batteries terminal voltage

Explanation;

Because at series connection the battery and resistor have equal voltage

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A northfield raider defensive back runs 20 m in 2.5 s what’s the average speed
Kaylis [27]
The average speed is 8 miles
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3 years ago
A busy chipmunk runs back and forth along a straight line of acorns that has been set out between his burrow and a nearby tree.
saveliy_v [14]

Answer: a = 1.32m/s2

Therefore, the average acceleration is 1.32m/s2

Explanation:

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a = change in velocity/time

a = ∆v/t

average acceleration a = (v2 -v1)/t. ....1

Given;

Final velocity v2 = 1.63m/s

Initial velocity v1 = -1.15ms

time taken t = 2.11s

Substituting into eqn 1

a = [1.63 - (-1.15)]/2.11

a = (1.63+1.15)/2.11

a = 2.78/2.11

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6 0
3 years ago
Suppose a horse leans against a wall as in the figure below.
Irina18 [472]

The force the horse and the rider exerts on the wall is equal to the weight combined acting in the opposite direction:

<h3>Force</h3>

Given Data

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When a body of mass rests on a surface, it exerts a force equal to the weight of the mass but opposite in direct on the mass/object

hence the force is computed as

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Force = 575 * 9.81

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Learn more about force here:

brainly.com/question/12970081

8 0
2 years ago
Two particles are located on the x axis. particle 1 has a mass m and is at the origin. particle 2 has a mass 2m and is at x = +l
wlad13 [49]

The solution would be like this for this specific problem:

<span>
The force on m is:</span>

<span>
GMm / x^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] -> 1

The force on 2m is:</span>

<span>
GM(2m) / (L - x)^2 + Gm(2m) / L^2 = 2[Gm (2m) / L^2] -> 2

From (1), you’ll get M = 2mx^2 / L^2 and from (2) you get M = m(L - x)^2 / L^2 

Since the Ms are the same, then 

2mx^2 / L^2 = m(L - x)^2 / L^2 

2x^2 = (L - x)^2 

xsqrt2 = L - x 

x(1 + sqrt2) = L 

x = L / (sqrt2 + 1) From here, we rationalize. 

x = L(sqrt2 - 1) / (sqrt2 + 1)(sqrt2 - 1) 

x = L(sqrt2 - 1) / (2 - 1) 


x = L(sqrt2 - 1) </span>

 

= 0.414L

 

<span>Therefore, the third particle should be located the 0.414L x axis so that the magnitude of the gravitational force on both particle 1 and particle 2 doubles.</span>

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natulia [17]
The answer to this question is D
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