Answer this one and u give you more points Need this now. This question has two parts. First, answer part A. Then, answer part B
1 answer:
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Answer:
<em>a. The rock takes 2.02 seconds to hit the ground</em>
<em>b. The rock lands at 20,2 m from the base of the cliff</em>
Explanation:
Horizontal motion occurs when an object is thrown horizontally with an initial speed v from a height h above the ground. When it happens, the object moves through a curved path determined by gravity until it hits the ground.
The time taken by the object to hit the ground is calculated by:
The range is defined as the maximum horizontal distance traveled by the object and it can be calculated as follows:
The man is standing on the edge of the h=20 m cliff and throws a rock with a horizontal speed of v=10 m/s.
a,
The time taken by the rock to reach the ground is:
t = 2.02 s
The rock takes 2.02 seconds to hit the ground
b.
The range is calculated now:
d = 20.2 m
The rock lands at 20,2 m from the base of the cliff
Answer:
a) t = 3.2 s
b)
Explanation:
a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:
En donde:
: es la altura inicial = 50 m
g: es la gravedad = 10 m/s²
Entonces, el tiempo requerido para llegar al suelo es 3.2 s.
b) La rapidez de la pelota justo antes del choque es el siguiente:
En donde:
: es la velocidad inicial = 0 (dado que se deja caer en resposo)
Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).
Espero que te sea de utilidad!