Answer:
The pressure in atm calculated using the van der Waals' equation, is 337.2atm
Explanation:
This is the Van der Waals equation for real gases:
(P + a/v² ) ( v-b) = R .T
where P is pressure
v is Volume/mol
R is the gas constant and T, T° in K
a y b are constant for each gas, so those values are data, from the statement.
[P + 1.345 L²atm/mol² / (0.7564L/10.21mol)² ] (0.7564L/10.21mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K
[P + 1.345 L²atm/mol² / 5.48X10⁻³ L²/mol²] (0.074 L/mol - 3.219×10-2 L/mol ) = 0.082 L.atm/mol.K . 296.9K
(P + 245.05 atm) (0.04181L/mol) = 0.082 L.atm/mol.K . 296.9K
(P + 245.05 atm) (0.04181L/mol) = 24.34 L.atm/mol
0.04181L/mol .P + 10.24 L.atm/mol = 24.34 L.atm/mol
0.04181L/mol .P = 24.34 L.atm/mol - 10.24 L.atm/mol
0.04181L/mol. P = 14.1 L.atm/mol
P = 14.1 L.atm/mol / 0.04181 mol/L
P = 337.2 atm
