C.)Cool air near the surface forms high-pressure areas; warm air forms low-pressure areas.
Explanation:
The relationship between air temperature and high and low pressure air is such that cool air near the surface forms high-pressure areas and warm air forms low pressure areas.
- Cool air is closer to the surface because it has low kinetic energy to move. It is denser.
- Warm air rises sharply away from the ground surface.
- They form low pressure areas and their molecules are wide apart due to their high kinetic energy. The air is less dense.
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1) Dawn dish soap has a density of 1.06 g/mL. If the mass of a sample of the liquid is 1.00 g what is the volume?
Answer:
v = 0.94 mL
Explanation:
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Given data:
Density of soap = 1.06 g/mL.
Mass = 1 g
Volume = ?
Solution:
d = m/v
v = m/d
v = 1 g/1.06 g/mL
v = 0.94 mL
2) Maple syrup has a density of 1.37 g.mL. What is the mass of 1.0 L of the maple syrup?
Answer:
m = 1370 g
Given data:
Density of soap = 1.37 g/mL.
Mass = ?
Volume = 1.0 L ( 1000 mL)
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
m = d × v
m = 1.37 g/mL × 1000 mL
m = 1370 g
3) The density of gasoline is 0.754 g/mL. A drop of gasoline has a mass of 22 g what is the volume?
Answer:
v = 29.2 mL
Given data:
Density of soap = 0.754 g/mL.
Mass = 22 g
Volume = ?
Formula:
D=m/v
D= density
m=mass
V=volume
Solution:
d = m/v
v = m/d
v = 22 g/0.754 g/mL
v = 29.2 mL
Amu valie on the top and abundsnce percent in decimals on the bottom for each isotope
