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3 years ago

Number of grams in four moles of BaCO3

Chemistry

1 answer:

Irina-Kira [14]3 years ago

5 0

This compound is also known as Barium Carbonate. 1 mole is equal to 1 moles BaCO3, or 197.3359<span> grams.</span>

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The molarity of a sodium hydroxide (NaOH) solution is 0.2 M. The molar mass of NaOH is 40 g/mol. If the solution contains 20 g o

mote1985 [20]

Answer:

$\large \boxed{\text{2.5 L}}$

Explanation:

1. Calculate the moles of NaOH.

$\text{Moles} = \text{20 g} \times \dfrac{\text{1 mol}}{\text{40 g}} = \text{0.50 mol}$

2. Calculate the volume of NaOH

$\begin{array}{rcl}\\\text{Molar concentration} &= &\dfrac{\text{moles}}{\text{litres}}\\\\ n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.2 mol}}{\text{1 L}} &=& \dfrac{\text{0.50 mol}}{V}\\\\ \dfrac{0.2V}{\text{1 L}} & = & 0.50\\\\0.2V &= & \text{0.50 L}\\V & = & \dfrac{\text{0.50 L}}{0.2}\\\\& = & \textbf{2.5 L}\\\end{array}\\\text{The volume of the solution is $\large \boxed{\textbf{2.5 L}}$}$

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4 years ago

Read 2 more answers

what is molarity of a sodium hydroxide solution made by combining 2.0 L of 0.60 M NaOH with 495 mL of 3.0 M NaOH? Assume the vol

hammer [34]

Answer:

Molarity of the sodium hydroxide solution is 1.443 M/L

Explanation:

Given;

0.60 M concentration of NaOH contains 2.0 L

3.0 M concentration of NaOH contains 495 mL

Molarity is given as concentration of the solute per liters of the solvent.

If the volumes of the two solutions are additive, then;

the total volume of NaOH = 2 L + 0.495 L = 2.495 L

the total concentration of NaOH = 0.6 M + 3.0 M = 3.6 M

Molarity of NaOH solution = 3.6 / 2.495

Molarity of NaOH solution = 1.443 M/L

Therefore, molarity of the sodium hydroxide solution is 1.443 M/L

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What type of bond would you expect in a compound of oxygen & sodium?

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4Na+O2--›2Na2O
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