Answer:
the measure of arc HG is 136
The question is incomplete. The complete question is as follows.
Consider the reduction of the rectangle. A large rectangle has a length of 16.8 feet and width of 2.3 feet. A smaller rectangle has a length of 4.5 feet and width of x feet. Not drawn to scale (The drawing is in the attachment). Rounded to the nearest tenth.
What is the value of x?
A. 0.1 feet
B. 0.6 feet
C. 1.6 feet
D. 2.0 feet
Answer: B. 0.6 feet
Step-by-step explanation: Two quantity are proportional if the ratio of them is constant. From the drawing and the question, we have that the two rectangles are proportional between them.


x = 
x = 0.6
The width of the smaller rectangle is <u>0.6 feet</u>.
The answer is B) y ≤ x + 1 and y > x - 3 . The graph shows TWO types of lines, a less than or equal to, and a greater than. B is the only answer with both of these lines.
Answer:
1248' x 2056' so I think you missed copying decimals but I would asume B
Step-by-step explanation:
312''x(1/(1/4''))=1248'
514''x(1'/(1/4''))=2056'
1 Simplify exponent
ma2cr+acar+car+ar+r=vacar
2 Simplify exponent
ma2cr+a2cr+car+ar+r=vacar
3 Factor out the common term r
r(ma2c+a2c+ca+a+1)=vacar
4 Cancel r on both sides
ma2c+a2c+ca+a+1=vaca
5 Subtract a2c from both sides
ma2c+ca+a+1=vaca−a2c
6 Factor out the common term ca
ma2c+ca+a+1=ca(va−a)
7 Subtract ca from both sides
ma2c+a+1=ca(va−a)−ca
8 Factor out the common term ca
ma2c+a+1=ca(va−a−(1))
9 Subtract a from both sides
ma2c+1=ca(va−a−1)−a
10 Factor out the common term a
ma2c+1=a(c(va−a−1)−1)
11 Subtract 1 from both sides
ma2c=a(c(va−a−1)−1)−1
12 Divide both sides by a2
mc=a(c(va−a−1)−1)−1a2
13 Divide both sides by c
m=a(c(va−a−1)−1)−1a2c