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Alexandra [31]
3 years ago
15

Venus is often called Earth's "twin." Describe TWO ways in which Earth and Venus are similar and TWO ways in which Earth and Ven

us are different.
Physics
1 answer:
insens350 [35]3 years ago
8 0

Venus is called Earth's "Twin" because Earth and Venus have almost the same mass, size, similar composition and they are neighboring planets. Some of most notable differences though between the two planets are their color, temperature, Earth's ability to support life and their atmosphere. Venus' atmosphere is about 100x thicker than Earth's, Earth can support life while Venus can not because Earth has water and plant life and Earth is a bright blue and green while Venus is more orange and red.

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А)
Anastaziya [24]

Answer:

4.5s

Explanation:

u=30m/s

v=50m/s

s=180m

a=constant(given)

By third equation of motion,    v  

2

=u  

2

+2as

(50)  

2

=(30)  

2

+2a(180)

a=  

3

40

​  

m/s  

2

 

By first equation of motion,    v=u+at

50=30+(  

9

40

​  

)t

t=  

2

9

​  

=4.5sec

4 0
2 years ago
Please select the word from the list that best fits the definition
enyata [817]

Answer:

conductor

Does not easily transfer electricity

8 0
3 years ago
Which of the following would not be useful in trying to correct spherical aberration a. using a combination lens made up of lens
Viefleur [7K]
A. Using a combination lens made up of lenses, each of which has a different index of refraction. Is the correct answer.
8 0
3 years ago
Read 2 more answers
You need to design a photodetector that can respond to the entire range of visible light. True or False
Rasek [7]

Answer: True

Explanation:

A photo detector that can respond to the entire rang of visible light can be design, it is true.

Photo detector is a device in an optical receiver which receives optical signals and convert it to electric signal. It is the key device position in front of the optical receiver.

7 0
3 years ago
A Carnot engine operates with an efficiency of 26.0% when the temperature of its cold reservoir is 281 K. Assuming that the temp
VLD [36.1K]

Answer:

The temperature of cold reservoir should be 246.818 K for efficiency of 35%

Explanation:

In first case we have given efficiency of Carnot engine = 26 % = 0.26

Temperature of cold reservoir T_L=281K

We know that efficiency of Carnot engine is given by

\eta =1-\frac{T_L}{T_H}

0.26 =1-\frac{281}{T_H}

T_H=379.72K

For second Carnot engine efficiency is given as 35% = 0.35

And temperature of hot reservoir is same so T_H=379.72K

So 0.35=1-\frac{T_L}{379.72}

T_L=246.818K

So the temperature of cold reservoir should be 246.818 K for efficiency of 35%

4 0
3 years ago
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