Answer:
Jedge = 0.076A/cm^2
Explanation:
If you want to know what is Jedge is convenient to use an integral. The total density current is given by:
(1)
But also, we have that the total current is
![I_T=J_TA\\\\J_T=\frac{I_T}{A}=\frac{1.5*10^{-3}A}{\pi(5*10^{-3})^2}=19.09\frac{A}{m^2}](https://tex.z-dn.net/?f=I_T%3DJ_TA%5C%5C%5C%5CJ_T%3D%5Cfrac%7BI_T%7D%7BA%7D%3D%5Cfrac%7B1.5%2A10%5E%7B-3%7DA%7D%7B%5Cpi%285%2A10%5E%7B-3%7D%29%5E2%7D%3D19.09%5Cfrac%7BA%7D%7Bm%5E2%7D)
where we have used that 5mm=5*10^{-3}m.
By replacing (1) we obtain:
![J_{edge}=\frac{2J_T}{R}=\frac{2(19.09A/m^2)}{5*10^{-3}m}=7639.4\frac{A}{m^2}=0.076\frac{A}{cm^2}](https://tex.z-dn.net/?f=J_%7Bedge%7D%3D%5Cfrac%7B2J_T%7D%7BR%7D%3D%5Cfrac%7B2%2819.09A%2Fm%5E2%29%7D%7B5%2A10%5E%7B-3%7Dm%7D%3D7639.4%5Cfrac%7BA%7D%7Bm%5E2%7D%3D0.076%5Cfrac%7BA%7D%7Bcm%5E2%7D)
hope this helps!!
The potential energy in the spring is given by:
![V = \frac{1}{2} kx^2](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20kx%5E2)
where k is the spring constant and x is the compression of the spring.
The work done by friction is given by:
![W = \int\limits {\overrightarrow F \cdot} \,\overrightarrow{ds} = F_{friction} s = \mu Ns = \mu mgs](https://tex.z-dn.net/?f=W%20%3D%20%5Cint%5Climits%20%7B%5Coverrightarrow%20F%20%5Ccdot%7D%20%5C%2C%5Coverrightarrow%7Bds%7D%20%3D%20F_%7Bfriction%7D%20s%20%3D%20%5Cmu%20Ns%20%3D%20%5Cmu%20mgs)
where s is the sliding distance, N the normal force N = mg, m is the mass of the block, g is the gravitational acceleration and μ is the coefficient of dynamic friction.
The work done by friction must be equal to the energy provided by the spring:
Answer:
G=GM/r^2
G=(6.67×10^-11)(6.39×10^23)/(3390000+400000)^2
G=(6.67×10^-11)(6.39×10^23)/(3790000)^2
G=2.967 m/s^2
Explanation:
Answer:
The Andrews is A. 90km
Explanation: so far 1cm is equal to 45km on the map. That Means that a unit distance on the map is actually 4, 500, 000units (i.e 45 x 1000 x 100) in real life.
So if 1 cm represents 45km
2cm will represent 2 x 45km which gives 90km.
When it crossed the sternum and is snug around the lap