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dedylja [7]
3 years ago
7

4NaCl + 2SO2 + _____H2O + _____O2 → _____Na2SO4 + 4HCl

Chemistry
1 answer:
Alik [6]3 years ago
3 0

The numbers that balance the following equation: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl is 2, 1, 2.

BALANCING EQUATION:

  • Balancing a chemical equation means to make sure that the number of atoms of each element on both sides of the equation are equal.

  • According to this question, the following chemical reaction are given: 4NaCl + 2SO2 + H2O + O2 → Na2SO4 + 4HCl

  • Some of the coefficients (numbers) have been placed there while some are missing. The equation that includes the missing coefficients (numbers) to balance the equation is:

4NaCl + 2SO2 + 2H2O + O2 → 2Na2SO4 + 4HCl

Learn more at: brainly.com/question/21049751?referrer=searchResults

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How many grams of solid iron will be produced from 32.1 grams of iron (III) oxide? Hint: Balance the equation first
Taya2010 [7]

Answer:

22.45g of Fe will be produced

Explanation:

The balanced reaction is:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g)

<em>Where 1 mole of Iron (III) oxide reacts with 2 moles of Iron</em>

<em />

To solve this question we have to find the moles of iron (III) oxide. With these moles and the balanced reaction we can find the moles of iron produced and its mass:

<em>Moles iron (III) oxide -Molar mass: 159.69g/mol-</em>

32.1g Fe₂O₃ * (1mol / 159.69g) = 0.201 moles Fe₂O₃

<em>Moles Iron:</em>

0.201 moles Fe₂O₃ * (2mol Fe / 1mol Fe₂O₃) = 0.402 moles of Fe

<em>Mass Fe -Molar mass: 55.845g/mol-</em>

0.402 moles of Fe * (55.845g/mol) =

<h3>22.45g of Fe will be produced</h3>
3 0
3 years ago
Why do we not know yet if we live in multiverse
kherson [118]

The people of he world believe and they don't believe.

I,myself, think we do land don't live in multiverse.

Why: Because in science I hear that there are many universes out there that need to b explored.

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How is mass described?
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7 0
4 years ago
Why is hydronium ion not an electrophile
galina1969 [7]

Answer:

Hydronium ion is not an electrophile because, its positive charge is on oxygen and its octet is filled.

Explanation:

5 0
3 years ago
How does the presence of a catalyst affect the enthalpy of a reaction? Group of answer choices 1. It depends on whether you are
Otrada [13]

Answer:

Option 3. The catalyst does not affect the enthalpy change (\Delta H_\text{rxn}) of a reaction.

Explanation:

As its name suggests, the enthalpy change of a reaction (\Delta H_\text{rxn}) is the difference between the enthalpy of the products and the reactants.

On the other hand, a catalyst speeds up a reaction because it provides an alternative reaction pathway from the reactants to the products.

In effect, a catalyst reduces the activation energy of the reaction in both directions. The reactants and products of the reaction won't change. As a result, the difference in their enthalpies won't change, either. That's the same as saying that the enthalpy change \Delta H_\text{rxn} of the reaction would stay the same.

Refer to an energy profile diagram. Enthalpy change of the reaction \Delta H_\text{rxn} measures the difference between the two horizontal sections. Indeed, the catalyst lowered the height of the peak. However, that did not change the height of each horizontal section or the difference between them. Hence, the enthalpy change of the reaction stayed the same.

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