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4 years ago

The steps in the melting of an ice-cream bar kept beside a bonfire are listed below:

Biology

2 answers:

Anna35 [415]4 years ago

6 0

Answer:

Heat is transferred by radiation in Step 1 and by conduction in Step 2.

Explanation:

laiz [17]4 years ago

4 0

The correct answer is D. Heat is transferred by radiation in Step 1 and by conduction in Step 2
radiation- the process of heat moving through the air
conduction- the process of heat moving from one object to another object by physical contact

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Explain why the intracellular and extracellular surfaces of the phospholipid bilayer are polar.

yulyashka [42]

Answer:

A single phospholipid molecule has a phosphate group on one end, called the “head,” and two side-by-side chains of fatty acids that make up the lipid “tails. ” The phosphate group is negatively charged, making the head polar and hydrophilic, or “water loving.” The phosphate heads are thus attracted to the water.

Explanation:

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3 0

2 years ago

2 or more cells can be connected in a battery ( true or false )

liberstina [14]

Answer:

Cells connect together to form a battery

Explanation

3 0

3 years ago

2. Dominant trait: cleft chin (C) Mother’s gametes: Cc

andre [41]

.2. Offspring Genotypes will be Cc or cc.

Offspring phenotypes : Cleft chin or no cleft chin.

% chance child will have cleft chin: 50%

3. % chance child will have arched feet: 25%

4. % chance child will have blonde hair: 50%

5. % chance child will have normal vision: 25%

Explanation:

CASE 1 :

Dominant trait: cleft chin (C)

Recessive trait: lacks cleft chin (c)

Father’s gametes: cc

Mother’s gametes: Cc

There are two possible combination of Gametes ,

C fom mother and c from father= Cc

c from mother and c from father = cc

Gametes of Cc Parents= $\frac{1}{2}C + \frac{1}{2} c$ ........(i)

Gametes of cc parents = $\frac{1}{2}c + \frac{1}{2}c$ .........(ii)

Combining (i) and (ii) we get,

$\frac{1}{2} Cc + \frac{1}{2} cc$

There fore offspring Genotypes will be Cc or cc

Offspring phenotypes :

Genotype Cc then phenotype= Cleft chin

Genotype cc then phenotype = Lacks cleft chin.

percentage chance child will have cleft chin = $\frac{0.5}{1}$ ×100

Therefore the chance is 50%.

CASE 2 :

Dominant trait: flat feet (A)

Recessive trait: arched feet (a)

Mother’s gametes: Heterozygous (Aa)

Father’s gametes: Heterozygous (Aa)

There are four possible combination of genotypes are =AA , Aa, Aa and aa

i.e. A from mother, A from father= AA

A from mother, a from father =Aa

a from mother, A from Father = Aa

a from mother, a from father = aa

Gametes of Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

Gametes of other Aa parent = $\frac{1}{2} A + \frac{1}{2} a$

..................................................................................

$\frac{1}{4} AA + \frac{1}{4} Aa$

+ $\frac{1}{4} Aa$ + $\frac{1}{4} aa$

..........................................................................................

$\frac{1}{4}AA + \frac{1}{2}Aa +\frac{1}{4} aa$

Offspring Genotypes will be: AA or Aa or aa

Offsprings phenotype will be:

Genotype AA then phenotype will be Flat feet

Genotype Aa then phenotype will be flat feet

Genotype aa then Phenotype will be arched feet.

Percentage chance child will have arched feet = $\frac{0.25}{1}$ × 100 = 25%

CASE 3:

Dominant trait: Brown hair (B)

Recessive trait: Blonde hair (b)

Mother’s gametes: Homozygous recessive (bb)

Father’s gametes: Heterozygous (Bb)

This case is very similar to the case 1 as one parent is homozygous recessive and other parent is heterozygous.

Resulting in half Bb and halve bb combination.

Genotypes will be Bb or bb

Phenotypes will be :

Genotype Bb then phenotype Brown hair

Phenotype bb then Phenotype bb.

% chance child will have blonde hair: 50%

CASE 4:

Dominant trait: farsightedness (F)

Recessive trait: normal vision (f)

Mother’s gametes: Heterozygous (Ff)

Father’s gametes: Heterozygous (Ff)

This Case is similar to case 2

it will result in one-fourth FF , half Ff and one-fouth ff combination.

Therefore Genotypes will be: FF, Ff and ff

Phenotypes:

Genotype FF then phenotype farsightedness

Genotype Ff then phenotype farsightedness

Genotype ff then phenotype normal vision.

% chance child will have normal vision: 25%

3 0

3 years ago

How do free energy machines work?

suter [353]

The machine is plugged into an electrical source, which gets the motor's wheel spinning. The machine is then unplugged and the wheel keeps spinning under its own inertia. Then electrical energy is extracted from the spinning wheel

8 0

3 years ago

Read 2 more answers

The chloroplasts of flowering land plants typically contain at least two photosynthetic pigments

SashulF [63]

Answer:

Chlorophyll A, and B.

Explanation:

Chlorophyll is known as the green pigment which is present in plants. Through the process of photosynthesis, It helps to convert solar light into useful energy. They have light absorption properties, so they are known as photoreceptors. Mainly two types of Chlorophyll are present in plants:

Chlorophyll A: It Is known as the primary photosynthetic pigment and has the ability to absorbs red, blue, and violet lights. Chlorophyll A is the location of the photochemical processes and can absorb light which is needed for the process of photosynthesis.

Chlorophyll B: It mainly helps to absorb blue light which is utilized to fill out the absorption of chlorophyll A it means it helps to supply additional light energy to chlorophyll A. It is known as the accessory pigment.

5 0

3 years ago