2 years ago

Pls help me with this…

Mathematics

1 answer:

Paladinen [302]2 years ago

5 0

3
The answer is 3
The answer is 3

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. Una persona desea realizar una pintura para su próxima exposición en donde esta tenga tres colores fluorescentes y dos colores

ycow [4]

Answer: B. 350.

Step-by-step explanation:

Given: Total number of fluorescent colors = 7

Total number of pastel colors = 5

Since , he want three fluorescent colors and two pastel colors.

Number of ways to select r things out of n things = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Number of ways to choose colors = $^7C_3\times\ ^5C_2$

$=\dfrac{7!}{3!4!}\times\dfrac{5!}{2!3!}\\\\=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}\times\dfrac{5\times4\times3!}{2\times3!}\\\\=350$

Hence, the correct option is B. 350.

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2 years ago

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3 years ago

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Can anyone help me refresh my mind?!

Nuetrik [128]

That is correct. The log3 stays the same and the numerator goes first and then the denominator goes second. When it’s a fraction like that one, the standard form would be subtraction.

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