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yulyashka [42]
2 years ago
6

4. What is the density of a substance that weighs 45 g and is 70 mL? (Density = g/mL)

Physics
1 answer:
AysviL [449]2 years ago
8 0

Answer:

<h2>0.64 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

d =  \frac{m}{v}  \\

m is the mass

v is the volume

From the question

m = 45 g

v = 70 mL

We have

d =  \frac{45}{70}  =  \frac{9}{14}  \\  = 0.6428571...

We have the final answer as

<h3>0.64 g/mL</h3>

Hope this helps you

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A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f
anzhelika [568]

Answer:

\phi_i = BA

Explanation:

magnetic flux is the count of magnetic field lines passing through a given loop or area

As we know that magnetic flux is given by the formula

\phi = \vec B. \vec A

here we also know that magnetic field B and plane of the coil is perpendicular in initial position

So the area vector is always perpendicular to the plane of the coil

so the angle between magnetic field and area vector is parallel to each other and this angle would be zero

so magnetic flux of the coil initially we have

\phi = BAcos0 = BA

6 0
3 years ago
Which of the following is not a true statement?<br> v=at<br> O art
shepuryov [24]

Answer:

t = Δa / v

Explanation:

To know which option is not true, we shall fine a relationship between acceleration (a), velocity (v), time (t) and radius (r). This is illustrated below:

Acceleration can simply be defined as the rate of change of velocity with time. Mathematically, it is expressed as shown below:

Acceleration = change in velocity / time

a = Δv / t ..... (1)

But

Δv = v₂ – v₁

Substitute the value of Δv into equation (1)

a = Δv / t

a = v₂ – v₁ / t ....... (2)

From equation (1), make Δv the subject of the equation.

a = Δv / t

Cross multiply

Δv = at .... (3)

From equation (1), make t the subject of the equation.

a = Δv / t

Cross multiply

at = Δv

Divide both side by a

t = Δv /a ...... (4)

From circular motion, centripetal's force is given by:

F = mv²/r

F = ma꜀

Therefore,

ma꜀ = mv²/r

Cancel out m

a꜀ = v²/r

SUMMARY:

a = Δv / t

a = v₂ – v₁ / t

Δv = at

t = Δv /a

a꜀ = v²/r

Considering the options given in question above, t = Δa / v is not a true statement.

8 0
3 years ago
A motorcycle that is slowing down uniformly covers 2.0 successive km in 80 s and 120 s, respectively. Calculate (a) the accelera
8090 [49]

Answer:

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

Explanation:

given data

distance d1 = 1 km

distance d2 = 2 km

time  t1 = 80 s

time t2 = 120 s + 80s = 200 s

to find out

acceleration and velocity at beginning and end

solution

we apply here law of motion that is

d = vt + 1/2×at²    

put value

1000 = v(80) + 1/2×a(80)²           ........................1

and

2000 = v(200) + 1/2×a(200)²      ........................2

so from equation 1 and 2 we get a and v

a = -0.042 m/s² and

v = 14.167 m/s

so by kinematic final velocity will be

V² = v² + 2ad

V² = (14.167)² + 2×(-0.042)×(2000)

V²  = 32.70

V = 5.7183 m/s

so

acceleration = -0.042 m/s²

velocity at beginning =  14.167 m/s

velocity at  end = 5.7183 m/s

8 0
3 years ago
For this situation to demonstrate a balanced force, how much force must Omar apply? (In the picture, Sam is pushing a box to the
11111nata11111 [884]
The answers 10N as it equals it out
3 0
3 years ago
Read 2 more answers
A particle in uniform circular motion requires a net force acting in what direction? Group of answer choices In the direction of
Annette [7]

Answer:

Towards the center of the circle

Explanation:

When an object is moving in uniform circular motion, it means that it is moving at a constant speed in a circular path.

In order to follows a circular path, the particle must have a net force acting on it, that it makes it constantly changing direction - and therefore, causing an acceleration - and this force is called centripetal force.

The direction of this centripetal force is always towards the centre of the circular path.

The nature of the centripetal force is always different, depending on the situation. For instance: for a satellite orbiting the Earth in circular motion, the centripetal force is provided by the force of gravity. For a car moving round a curve, the centripetal force is provided by the force of friction between the tyres and the road.

The magnitude of the centripetal force is given by

F=m\frac{v^2}{r}

where

m is the mass of the object

v is its speed

r is the  radius of the circle

3 0
3 years ago
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