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Sergio039 [100]

2 years ago

5

Help me please!!!! please be quick!!

1 answer:

kiruha [24]2 years ago

5 0

Answer:

40m^2 e

Step-by-step explanation:

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I need the answer please.

Anestetic [448]

2 1/4 = 9/4

(9/4)(8/5) = (9/1)(2/5) = 18/5 = 3 3/5 cups

5 0

3 years ago

The area of this parallelogram is 120 ft2 find the value of h

Free_Kalibri [48]

Answer: 60

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Whole-wheat bread costs $2.06/lb. How much would 3.8 lb of whole-wheat bread cost?

Xelga [282]

Whole-wheat bread = $2.06/lb

We need the cost of 3.8 lbs of whole-wheat bread.

So, we simply need to multiply the cost with the amount needed.

(cost per pound) × (amount of bread)

($2.06) × (3.8)

Simplify.

$7.828

Round to the nearest tenths.

$7.83

So, 3.8 pounds of whole wheat bread costs $7.83

~Hope I helped!~

7 0

3 years ago

Read 2 more answers

4) 8(-2 + 2n) + 3n = 40 +5n

Nikitich [7]

Answer:

use the distributive property to distribute the 8

-16+16n+3n=40+5n

-16+19n=40+5n

-16=40+5n-19n

-16=40-14n

-14n+40= -16

-14n= -16-40

-14n= -56

n= -56/-14

n= 4

5 0

2 years ago

Read 2 more answers

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

<u>Answer-</u> Length of the curve of intersection is 13.5191 sq.units

<u>Solution-</u>

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

8 0

3 years ago