Question

Calculate the root mean square velocity of the nitrogen molecules, in meters per second (m/s). Do not include the unit of measure in your answer.

Answer 1

This question involves the concepts of average kinetic energy and velocity.

Complete question: Calculate the root mean square velocity of the nitrogen molecules, at 25°C, in meters per second (m/s). Do not include the unit of measure in your answer.

The root mean square velocity of the nitrogen molecule at 25°C is "727.66 m/s".

The average kinetic energy of gas molecules is given by the following formula:

$K.E=\frac{3}{2}KT$

Also,

$K.E = \frac{1}{2}mv^2$

Comparing both equations we get:

$\frac{3}{2}KT=\frac{1}{2}mv^2\\\\v=\sqrt{\frac{3KT}{m}}$

where,

v = root men square velocity = ?

K = Boltzman's constant = 1.38 x 10⁻²³ J/k

T = absolute temperature = 25°C + 273 = 298 k

m = mass of nitrogen molecule = 2.33 x 10⁻²⁶ kg

Therefore,

$v=\sqrt{\frac{3(1.38\ x\ 10^{-23}\ J/k)(298\ k)}{2.33\ x\ 10^{-26}\ kg}}$

v = 727.66 m/s

Learn more about the root mean square velocity here:

brainly.com/question/2020688?referrer=searchResults