Question

If a single circular loop of wire carries a current of 61 A and produces a magnetic field at its center with a magnitude of 1.70 10-4 T, determine the radius of the loop.

Answer 1

Answer:

The  radius is  $R = 0.22 5 \ m$

Explanation:

From the question we are told that

    The current is  $I = 61 \ A$

     The  magnetic field is  $B = 1.70 *10^{-4} \ T$

Generally the magnetic field produced by a current carrying conductor  is mathematically represented as

        $B = \frac{\mu_o * I}{2 * R }$

=>     $R = \frac{\mu_o * I }{ 2 * B }$

Here  $\mu_o$ is the permeability of free space with value  $\mu_o = 4\pi * 10^{-7} N/A^2$

=>    $R = \frac{ 4\pi * 10^{-7} * 61 }{ 2 * 1.70 *10^{-4} }$

=>  $R = 0.22 5 \ m$