Answer:
Explanation:
It is given that,
Mass of the baseball, m = 0.14 kg
It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :
h = 1.8 m
u = 5.93 m/s
Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :
h' = 1.4 m
v = -5.23 m/s
The change in the momentum of the ball is given by :
So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.
<span>With a half-life of 700 million years, U-235 would have had twice as much mass at a time 700 MYA. This would have put the mass at 100kg at that time. Going back another 50 million years would be (50/700) or 1/14 of the half-life, or (1/2 * 1/14), or 1/28 of the total mass. 1/28 of 100kg is 3.57kg, so the amount present at the 750MYA mark would be approximately 103.57kg of U-235.</span>
Explanation:
The given data is as follows.
Charge (q) = 2 coulomb, Force (F) = 60 N
Now, it is known that the relation between electric field, force and charge is as follows.
Magnitude of electric field (E) = 
Hence, putting the given values into the above formula as follows.
Electric field (E) =
= 
= 30 N/C
Thus, we can conclude that the magnitude of the electric field at the place where the charge is located is 30 N/C.
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Period is the inverse of freguency (1/f) and freqquency is the inverse of period (1/p)
