Plz, tell me the answer. and plz explain if you can
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- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
so 
and
so 
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
- tan²x + sec²x = 1 or 1 + tan²x = sec²x
sin²x + cos²x = 1
Divide the whole by cos²x
and
Therefore,
tan²x + 1 = sec²x
Take tan²x to the other side {You will have the same answer}
1 = - tan²x = sec²x or sec²x - tanx = 1
Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
*9
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(*9)*
, or dividing everything by 4.
(*9)/4
Finally, subtract three.
The final equation would read:
((*9)*)-3
Using PE(M/D)(A/S), we'd start with*9
3 and 9 cancel out to be 1 and 3, leaving us with
, or 8, and 3 and this part of the equation reading 8*3, which is 24.
The next step is
, which is 6.
Lastly we subtract 3 from six, leaving us 3.
Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
(
, or dividing everything by 4.
(
Finally, subtract three.
The final equation would read:
((
Using PE(M/D)(A/S), we'd start with
3 and 9 cancel out to be 1 and 3, leaving us with
The next step is
Lastly we subtract 3 from six, leaving us 3.