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allsm [11]
3 years ago
9

2,601,400,070 written out ?

Mathematics
1 answer:
Sholpan [36]3 years ago
7 0

Answer:

two billion six hundred one million four hundred thousand seventy

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Factor:<br> 4tan^2x-(4)/(cotx)+sinx(cscx) ...?
lisov135 [29]
4tan^(2)x-((4)/(cotx))+sinxcscx 


Multiply -1 by the (4)/(cotx) inside the parentheses. 

4tan^(2)x-(4)/(cotx)+sinxcscx 


To add fractions, the denominators must be equal. The denominators can be made equal by finding the least common denominator (LCD). In this case, the LCD is cotx. Next, multiply each fraction by a factor of 1 that will create the LCD in each of the fractions. 


4tan^(2)x*(cotx)/(cotx)-(4)/(cotx)+sin... 


Complete the multiplication to produce a denominator of cotx in each expression. 

(4tan^(2)xcotx)/(cotx)-(4)/(cotx)+(cot... 


Combine the numerators of all expressions that have common denominators. 
<span>
(4tan^(2)xcotx-4+cotxsinxcscx)/(cotx)</span>
8 0
3 years ago
13 cans of vegetables and 14 of soup. They put the cans in bags with 3 cans in each bag how many bags of cans did they have .
igomit [66]

Answer:

9

Step-by-step explanation:

13 + 14 = 27

27 / 3 = 9 cans.

4 0
3 years ago
A counselor at a community college claims that the mean GPA for students who have transferred to State University is more than 3
Lena [83]

Answer:

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

Step-by-step explanation:

Data given and notation  

\bar X=3.25 represent the sample mean

s=0.3 represent the sample standard deviation

n=36 sample size  

\mu_o =3.1 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is more than 3.1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 3.1  

Alternative hypothesis:\mu > 3.1  

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{3.25-3.1}{\frac{0.3}{\sqrt{36}}}=3  

P-value  

The first step is calculate the degrees of freedom, on this case:  

df=n-1=36-1=35  

Since is a one right tailed test the p value would be:  

p_v =P(t_{(35)}>3)=0.00247  

Conclusion  

If we compare the p value and the significance level for example \alpha=1-0.99=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.

And the best conclusion would be:

a) Yes. The counselor's claim is valid

Because we reject the null hypothesis in favor to the alternative hypothesis.

5 0
3 years ago
Solve this problem using 3.14 for pi. The diameter of this Frisbee is 12 inches. What’s the circumference of this Frisbee?
Ludmilka [50]
Circumference= diameter x pi
12x3.14 = 37.68
8 0
3 years ago
A truck weighs 72429 pounds.when rounded to the nearest ten-thousands the truck's weight will be
NARA [144]
72,429 rounded to the nearest ten-thousands is 70,000.
4 0
3 years ago
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