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shutvik [7]
2 years ago
10

How much larger is the diameter of Jupiter compared to the diameter of Saturn?

Physics
1 answer:
allsm [11]2 years ago
5 0
Really long we’ll not long but far in distance
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A proton that has a mass m and is moving at 270 m/s in the i hat direction undergoes a head-on elastic collision with a stationa
Nataly_w [17]

Answer:

V_p = 267.258 m/s

V_n = 38.375 m/s      

Explanation:

using the law of the conservation of the linear momentum:

P_i = P_f

where P_i is the inicial momemtum and P_f is the final momentum

the linear momentum is calculated by the next equation

P = MV

where M is the mass and V is the velocity.

so:

P_i = m(270 m/s)

P_f = mV_P + M_nV_n

where m is the mass of the proton and V_p is the velocity of the proton after the collision, M_n is the mass of the nucleus and V_n is the velocity of the nucleus after the collision.

therefore, we can formulate the following equation:

m(270 m/s) = mV_p + 14mV_n

then, m is cancelated and we have:

270 = V_p + 14V_n

This is a elastic collision, so the kinetic energy K is conservated. Then:

K_i = \frac{1}{2}MV^2 = \frac{1}{2}m(270)^2

and

Kf = \frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2

then,

\frac{1}{2}m(270)^2 =  \frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2

here we can cancel the m and get:

\frac{1}{2}(270)^2 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2

now, we have two equations and two incognites:

270 = V_p + 14V_n  (eq. 1)

\frac{1}{2}(270)^2 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2

in the second equation, we have:

36450 =  \frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2  (eq. 2)

from this last equation we solve for V_n as:

V_n = \sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }

and replace in the other equation as:

270 = V_p + 14\sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }

so,

V_p = -267.258 m/s

Vp is negative because the proton go in the -i hat direction.

Finally, replacing this value on eq. 1 we get:

V_n = \frac{270+267.258}{14}

V_n = 38.375 m/s  

3 0
3 years ago
What is frictional less pulley​
Talja [164]

Answer:

Conditions under which the belt and pulleys are operating – The friction between the belt and pulley may decrease substantially if the belt happens to be muddy or wet, as it may act as a lubricant between the surfaces.

Explanation:

I hope that this would be helpful

7 0
2 years ago
As an object falls
Sidana [21]
As an object falls in response to gravitational force, its velocity increases
and its acceleration is unchanged.  On Earth, its acceleration is 9.8 m/s².
3 0
2 years ago
Read 2 more answers
Jody does long distance running and also strength trains twice a week.
murzikaleks [220]

<u>Answer:</u>

<em>Jody will have strong bones and show muscle hypertrophy. </em>

<u>Explanation:</u>

Long distance running practiced regularly helps in <em>increasing the strength of bones</em>. Muscular hypertrophy is the increase in mass of skeletal muscles due to the increase in the size of myofibrils or increase in muscle glycogen storage. <em>Strength training exercises</em> performed regularly induce muscular hypertrophy.

During strength <em>training exercises muscles</em> undergo contraction and repeated contraction breaks muscle fibres. New muscle fibres are added as a means of repair and this happens at the relaxing phase of muscles. More muscle fibres are added to <em>compensate the damage and thus muscle mass increases. </em>

6 0
3 years ago
An 800-W heater raises the temperature of 4 kg of soup by 40 °C in 13 minutes.
Tju [1.3M]

Answer:

Q=0.16*c kJ

Explanation:

Heat transfer and energy changes is related by the equation

Q=mcΔT

where

Q=heat transfer

m=mass of substance

c=specific heat of the material

ΔT= change in temperature

Given

m= 4 kg

c=c

ΔT=40° C

Q=4*c*40

Q=160c

Q=160/1000*c kJ

Q=0.16*c kJ

6 0
3 years ago
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