ΔH2 = - δH1 δH2 = - 2 x δH1 δH2 = 2 x <span>δ</span>H1
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<span>-Boron (B)
-Silicon (Si)
-Germanium (Ge)
-Arsenic (As)
-Antimony (Sb)
-Tellurium (Te)
-Polonium (Po)
<span>-Astatine (At)</span></span>
Answer:

Explanation:
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In this case, according to the chemical reaction by which HBr reacts with Ba(OH)2:

We can see there is a 2:1 mole ratio between the acid and the base; thus, at the equivalent point we can write:

Therefore, for is to compute the volume of the used base, we proceed as shown below:

And we plug in to obtain:

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