1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alukav5142 [94]
3 years ago
11

Search...

Chemistry
2 answers:
denis23 [38]3 years ago
6 0
Answer: The answer is the second one
Ira Lisetskai [31]3 years ago
6 0
49484477337282828383838292
You might be interested in
What is the mass of OH- in Ca(OH)2
Ne4ueva [31]
Oxygen: 16.00 g/mol
Hydrogen: 1.01 g/mol

The mass would be 17.01 g/mol
5 0
3 years ago
Write the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2). You do not need to make t
Soloha48 [4]
For the answer to the question above, asking to w<span>rite the complete balanced equation for the reaction between aluminum metal (Al) and oxygen gas (O2)and You do not need to make the subscripts smaller.
My answer would be,
</span><span>4Al(s) + 3O2(g) --->2 Al2O3(s)
</span>
I hope this helps.
3 0
3 years ago
do you agree or not that evidence is only used to back scientific laws and provide evidence why or why not!!!!!! thank you, will
suter [353]

Answer:

yes, because evidence from scientifically research studies, is important because it lets us make decisions based on what works with studies of science we can know if this is right or not  

Explanation:

Hope i helped~  

4 0
3 years ago
The reaction 2a → a2​​​​​ was experimentally determined to be second order with a rate constant, k, equal to 0.0265 m–1min–1. if
katovenus [111]

The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

where, [A]t= the concentration of A at time t,

[A]0= the concentration of A at time t=0

<span>k =</span> the rate constant for the reaction


<u>Given</u>: [A]0= 4 M, k = 0.0265 m–1min–1 and t = 180.0 min


Hence, \frac{1}{[A]t} = \frac{1}{4} + (0.0265 X 180)

<span>                                        = 4.858</span>

<span><span><span>Therefore, [A]</span>t</span>= 0.2058 M.</span>

<span>
</span>

<span>Answer: C</span>oncentration of A, after 180 min, is 0.2058 M

7 0
3 years ago
Read 2 more answers
Consider only the experiment you conducted with 0.5 g. of lactose.
rjkz [21]
Answer is: <span>the pH value(level) is the independent variable.</span><span>
</span>
Missing question: <span>We conducted an experiment where we added 0.5 g of lactose to 5 different test tubes all containing 5 different pH levels. What is the independent variable?
In this experiment pH level changes, so results depend on different pH values.
Mass of lactose is same during experiment,so t</span>he number of molecules of product formed per minute is the <span>dependent variable.</span>
8 0
4 years ago
Other questions:
  • What are the measurements for standard temperature and pressure (stp)? kp?
    14·1 answer
  • Glycerol (C3H8O3), also called glycerine, is widely used in the food and pharmaceutical industries. Glycerol is polar and dissol
    6·1 answer
  • Temperature is used to measure the movement of particles such as atoms and molecules. as temperature increases, what is true of
    6·1 answer
  • Y do students have to go to school, I mean Do we have to learn we can learn at home ∞∵
    13·2 answers
  • Explain why the population of trout might increase if the population of frogs decreased
    5·1 answer
  • Here’s another science question;( one more after this !
    10·1 answer
  • What is the pOH of a 0.00037 M solution of barium hydroxide
    12·1 answer
  • How many moles of Mg(OH)2 will react with 2.5 mol HCI?
    10·1 answer
  • How many electrons are in an ion of calcium (Ca2+)?<br> A. 2<br> B. 18<br> C. 0<br> D. 22
    7·1 answer
  • PLEASE HELP!!!!! Is it as critcal for your tap water to be a good buffer as it is for the water at the nearest lake to be a good
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!