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Sergeu [11.5K]
3 years ago
7

Three coins are tossed onto a table and the numbers of heads is recorded. The number of possible outcomes for this event is

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
5 0

Answer:

4!

Step-by-step explanation:

4 is correct, since there will be no heads, one head and two tails, two heads and one tail, or three heads. Notice that the order is not involved here.

Ivenika [448]3 years ago
4 0
1 coin has 2 sides. Multiply 2 × 3 to get the total number of outcomes.
2 × 3 = 6
There are 3/6 Possible outcomes.
Remember, they are looking for the number of heads, not both.
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dusya [7]

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-- The weight HASTA be 40 pounds or less.  It can't be more.

-- 40 pounds is OK, and anything less than 40 pounds is OK too.

-- 41 pounds or more is too much.

-- Here are all the OK conditions:
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3 years ago
Suppose you purchase a bundle of 18 bare-root broccoli plants. The sales clerk tells you that on average you can expect 8% of th
neonofarm [45]

Answer:

There is a 57.18% probability that you will lose at most 1 of the broccoli plants.

Step-by-step explanation:

For each plant, there are only two possible outcomes. Either they die, or they do not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem, we have that

There are 18 plants, so n = 18.

8% of the plants die before producing any broccoli. So p = 0.08.

Use the binomial formula to find the probability that you will lose at most 1 of the broccoli plants.

This is

P = P(X = 0) + P(X = 1)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.08)^{0}.(0.92)^{18} = 0.2229

P(X = 1) = C_{18,1}.(0.08)^{1}.(0.92)^{17} = 0.3489

P = P(X = 0) + P(X = 1) = 0.2229 + 0.3489 = 0.5718

There is a 57.18% probability that you will lose at most 1 of the broccoli plants.

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almond37 [142]

Answer:

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Step-by-step explanation:

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