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Anarel [89]
3 years ago
9

The opposite diagram shows two small planets of mass m each, and one larger planet of mass 4m, aligned and separated by distance

d between each other.
Which planet (or planets) is affected by the greatest net gravitational force?

Physics
1 answer:
velikii [3]3 years ago
6 0

Answer:

c-160

Explanation:

since \frac{G.M.m}{R^{2} }=20 N

so the Equation after doubling the the mass of each and object and dividing the radius by 2 (note that the 2 must be also under the power)

so the equation will be \frac{G.2M.2m}{\frac{1 }{4}R^{2} } which equals 8*\frac{G.M.m}{R^{2} }, so the force will be 8*20 =160

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(a) How fast must a 3000-kg elephant move to have the same kinetic energy as a 65.0-kg sprinter running at 10.0 m/ s?
Aleksandr-060686 [28]

Answer:

1.4719 m per sec

Explanation:

Hello

Kinetic energy is the energy associated with the movement of objects. Although there are many forms of kinetic energy  

the formula to use is

E=\frac{mv^{2} }{2}

where m is the mass of the object and v the velocity

lets see the kinetic energy of the sprinter running

E=\frac{65 Kg*10(\frac{m}{s} ^)){2} }{2} \\\\E=\frac{65 *100 }{2} \\E=3250 Joules\\\\

Now, the elephant must have the same kinetic energy

E=\frac{m*v_{2} ^{2} }{2} \\\\E*2=m*v_{2} ^{2}\\ \frac{2E}{m} =v_{2} ^{2} \\\sqrt{\frac{2E}{m} } =v_{2}  \\\\\\v_{2} =\sqrt{\frac{2*3250}{3000} }\\ \\v_{2} =1.4719 \frac{m}{s} \\\\

it works only the positive root, so the elephant must to  walk  to 1.4719 m/s to have the same kinetic energy.

Have a great day

8 0
3 years ago
A 7000-kg plane is launched from an aircraft carrier in 2.0 seconds
ExtremeBDS [4]

The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively

To calculate the acceleration of the plane, we use the formula below.

<h3>Formula:</h3>
  • a = F/m..................... Equation 1

Where:

  • a = Acceleration of the plane
  • F = Force applied to the plane
  • m = mass of the plane.

From the question,

Given:

  • F = 550000 N
  • m = 7000 kg

Substitute these values into equation 1

  • a = 550000/7000
  • a = 78.57 m/s²

To calculate the velocity, we use the formula below.

  • v = u+at............. Equation 2

Where:

  • v = Final velocity
  • u = initial velocity
  • a = acceleration
  • t = time.

From the question,

Given:

  • u = 0 m/s
  • a = 78.57 m/s
  • t = 2.0 seconds

Substitute these values into equation 2

  • v = 0+2(78.57)
  • v = 157.14 m/s

Hence, The acceleration and velocity of the plane is 78.57 m/s² and 157.14 m/s respectively.
Learn more about acceleration here: brainly.com/question/460763

5 0
2 years ago
When the ball is thrown upward and is on the way up what is the direction of it's acceleration?
nalin [4]
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5 0
3 years ago
A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci
larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

#SPJ1

6 0
2 years ago
Lars is standing near the edge of a 90-meter cliff. He throws a ball upward, but does not catch it, and it falls to the bottom o
Kipish [7]

Answer:

c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

S = ut + \frac {1}{2}at^{2}

Where;

  • S represents the displacement or height measured in meters.
  • u represents the initial velocity measured in meters per seconds.
  • t represents the time measured in seconds.
  • a represents acceleration measured in meters per seconds square.

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

90 = u*5.55  + \frac {1}{2}*(-9.8)*5.55^{2}

90 = u5.55 - 4.9*30.8025

90 = u5.55 - 150.93225

Rearranging the equation, we have;

u5.55 = 90 + 150.93225

u5.55 = 240.93225

u = \frac {240.93225}{5.55}

Initial velocity, u = 43.41 ≈ 41 m/s

4 0
3 years ago
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