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Black_prince [1.1K]
3 years ago
8

If only one external force acts on a particle, does it necessarily change the particle's kinetic energy and velocity? (Select al

l that apply.) Particle's kinetic energy won't change. Particle's kinetic energy may or may not change. Particle's kinetic energy must change. Particle's velocity won't change. Particle's velocity may or may not change. Particle's velocity must change.
Physics
1 answer:
Rina8888 [55]3 years ago
4 0

Answer:

Option 3 and 6

Explanation:

If the particle is under the action of only one external force, both its kinetic energy and the velocity must vary.

When the particle is exerted by an external force, then this external force tends to accelerate the particle.

When the particle accelerates, its velocity must vary for that acceleration to occur.

When the velocity of the particle changes then its Kinetic energy must vary with the velocity of the particle.

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A current of 200 mA through a conductor converts 40 joules of electrical energy into heat in 30 second
Komok [63]

Answer:

V = 6.65 [volt]

Explanation:

First, we must calculate the power by means of the following equation, where the voltage is related to the energy produced or consumed in a given time.

P=E/t\\P = 40/30\\P = 1.33[s]

Using the power we can calculate the voltage, by means of the following equation that relates the voltage to the current.

P=V*I

where:

V = voltage [Volts]

I = current = 200 [mA] = 0.2 [A]

V = 1.33/0.2\\V = 6.65 [volt]

8 0
3 years ago
Identify the generic outer electron configuration for the halogens.
Delicious77 [7]
<span>The Halogen outer layer is considered to be full with eight electrons. Halogen is also considered to be part of the Noble gases classification. The exchange of electrons in the halogen atom renders a photon energy pulse with produces light. The consentrated light spectrum is produced in the halogen light bulbs and halogen laser products.</span>
8 0
4 years ago
If this did not happen, what would be the approximate force on an eardrum of area 0.22 cm2 if a change in altitude of 1500 m tak
jeyben [28]

Complete Question

When you ascend or descend a great deal when driving in a car yours ears "pop," which means that the pressure behind the eardrum is being equalized to that outside. If this did not happen, what would be the approximate force on an eardrum of area .50 cm2 if a change in altitude of 950 m takes place?

Answer:

The value is F    = 0.60 \  N

Explanation:

From the question we are told that

   The area of the ear drum is  A = 0.5 \  cm^2 = 0.50 *10^{-4} \  m^2

    The change in altitude is  \Delta d  = 950 \  m

Generally the change in pressure is mathematically represented as

       \Delta P = \frac{F}{A}

This can also be mathematically represented as

      \Delta P = \rho * g *  \Delta d

So

       \frac{F}{A}     = \rho * g *  \Delta d

=>    F    = \rho * g *  \Delta d  *  A

=>    F    = \rho * g *  \Delta d  *  A

Here \rho is the density of dry air with value  \rho =  1.29 \ kg /m^3

So

     F    = 1.29 * 9.8 *  950  *  0.50 *10^{-4}

=> F    = 0.60 \  N

3 0
3 years ago
on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. what is the velocity (speed and direction)
kiruha [24]

Velocity is the rate of change of position of an object. The velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

<h3>What is Velocity?</h3>

Velocity is the directional speed of a moving object as an indicator of its rate of change in location as perceived from a certain frame of reference and measured by a specific time standard.

Given that on a day the wind is blowing towards the south at 7 m/s, a runner jogs west at 7 m/s. Therefore, the velocity of the air relative to the runner can be written as,

Relative velocity = √[(Velocity of the jogger)² + (Velocity of the air)²]

                            = √[(5)² + (5)²]

                            = √(25 + 25)

                            = √50

                            = 5√2 m/sec

The direction of the relative velocity is,

The angle of relative Velocity = Tan(θ)

Tan(θ) = Vertical velocity / Horizontal velocity

Tan(θ) = 5/5

Tan(θ) = 1

θ = tan⁻¹(1)

θ = 45°

Since this angle is formed between the two velocities, therefore, the direction of the velocity is southwest.

Hence, the velocity of the air relative to the runner is 5√2 m/sec and it is in the southwest direction.

Learn more about Velocity here:

brainly.com/question/18084516

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4 0
1 year ago
A nail is hit with a hammer. Which type of contact force has been applied?
Mademuasel [1]
Applied force I think.

5 0
4 years ago
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