(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
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(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:
There is one possible solution
Step-by-step explanation:
Here, we want to get the number of solutions
We can proceed to solve the equation
we have two y values so we can directly equate the x parts
-2x - 4 = 3x + 3
3x + 2x = -3-4
5x = -7
x = -7/5
To get y, we substitute
We can only get one value of y too
So we have a point (x,y) as the solution to the system of equations
Answer:
y=3x-1
Step-by-step explanation:
y=mx+b
y=3x+b
y=3x-1
The answers is C. because when you do 180/3-15 you get 45 as the answer.
Answer: q=0.3p-2
Well everytime P goes up by one then Q goes up by positive 0.3
