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Vinvika [58]
4 years ago
10

A solution of water (kb=0.512 ?c/m) and glucose boils at 103.06 ?c. what is the molal concentration of glucose in this solution?

assume that the boiling point of pure water is 100.00 ?c.
Chemistry
2 answers:
AfilCa [17]4 years ago
6 0

Answer:

 

100.26°C

Explanation:

nirvana33 [79]4 years ago
4 0
<span>When a solute is added to a solvent, some properties are affected and these set of properties are called colligative properties. The properties depend on the amount of solute dissolved in a solvent. For this we use the boiling point elevation of the solution. We do as follows:

</span>ΔT(boiling point) = 103.06 °C - 100.0 °C= 3.06 °C<span>
ΔT(boiling point)  = (Kb)m
m = </span>ΔT(boiling point) / Kb<span>
m =  3.06 °C / 0.512 °C kg / mol
m = 5.98 mol / kg

</span>
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