Answer:
a. Oxygen gas is limiting
Explanation:
hydrogen gas and oxygen gas are reacted to form water
2H₂ + O₂ → 2H₂O
the above balanced equation shows that 2 moles of H₂ is required for 1 mole of O₂
Given equal masses of H₂ and O₂
assuming 'x' gm for each, no. of moles of each gas =
no. of moles of H₂ = x/2 = 0.5x moles
no.of moles of O₂ = x/32 = 0.031x moles
This shows that no. of moles of O₂ is very less so O₂ will become the limiting reagent.
Answer:
Answer choice B
Explanation:
Since you do not know the volume of the liquid in each beaker, the one in the smaller beaker could have more substance and therefore more thermal energy. If they had the same amount of substance, then the more voluminous one would radiate faster. However, since you do not know this, there is no way to tell. PM me if you have more questions. Hope this helps!
Answer: What conclusion can be drawn from the statement that an element has high ionization energy and small atomic size? The element is most likely from Group 1A or 2A and in period 1 or 2. Describe how the atomic radius of an element is related to metallic character.
Explanation:
Answer:
15.4 g
Explanation:
The reaction that takes place is:
- 2C₅H₁₀ + 15O₂ → 10CO₂ + 10H₂O
First we <u>convert 5 grams of C₅H₁₀ into moles</u>, using its <em>molar mass</em>:
- 5 g ÷ 70 g/mol = 0.07 mol C₅H₁₀
Then we <u>convert C₅H₁₀ moles into CO₂ moles</u>, using the <em>stoichiometric coefficients</em> of the reaction:
- 0.07 mol C₅H₁₀ *
= 0.35 mol CO₂
Finally we <u>convert 0.35 moles of CO₂ into grams</u>:
- 0.35 mol CO₂ * 44 g/mol = 15.4 g
