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Bumek [7]
2 years ago
13

Key Na CE с - What does it mean if a compound ends in -ide?​

Chemistry
1 answer:
astra-53 [7]2 years ago
5 0

Answer:

<u>This means that there are only two elements in the compound . </u>

Explanation:

N/A .

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Complete the following table. Tell if the molecule is polar or nonpolar, draw the Lewis dot structure for the molecule, tell wha
andrew11 [14]

The complete table is shown in figure

a) NH3 is polar as the bonds between N and H are polar. Due to asymmetry in   the molecule the molecule is polar

The shape of molecule is trigonal pyramidal while its electronic geometry is tetrahedral.

b) CO2: it is a non polar molecule with polar bonds. The molecule becomes non polar as the dipole moment cancel each other. [Dipole moment is a vector quantity]

The shape is linear.

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3 years ago
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Serga [27]

I think its prokaryotes?

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What do the coefficients in front of the reactants and products in a chemical reaction represent ?
makvit [3.9K]

It indicates the number of moles of reactants and products

Explanation:

The coefficients in front of the reactants and products in a chemical reaction represents the number of moles of reactants and products.

Every reaction is made up of equal number of moles of reactants and products. Thus, chemical equations are written in such a way to obey the law of conservation of matter.

The numbers used are usually whole numbers and the are very important in stoichiometry.

learn more:

Number of moles brainly.com/question/1841136

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4 0
3 years ago
What is the density of an object having a mass of 4.0 g and a volume of 30 mL?
RUDIKE [14]

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3 years ago
How much heat is released when 75 g of octane is burned completely if the enthalpy of combustion is -5,500 kJ/mol CsH18? C8H18 +
aalyn [17]

Answer : The correct option is, (D) 3600 kJ

Explanation :

Mass of octane = 75 g

Molar mass of octane = 114.23 g/mole

Enthalpy of combustion = -5500 kJ/mol

First we have to calculate the moles of octane.

\text{ Moles of octane}=\frac{\text{ Mass of octane}}{\text{ Molar mass of octane}}=\frac{75g}{114.23g/mole}=0.656moles

Now we have to calculate the heat released in the reaction.

As, 1 mole of octane released heat = -5500 kJ

So, 0.656 mole of octane released heat = 0.656 × (-5500 kJ)

                                                                   = -3608 kJ

                                                                   ≈ -3600 kJ

Therefore, the heat released in the reaction is 3600 kJ

5 0
2 years ago
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