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Mars2501 [29]
3 years ago
12

If an atom of nitrogen binds with three hydrogen atoms to form a molecule of ammonia, how many lone pairs of electrons does nitr

ogen have?
A.
one
B.
three
C.
four
D.
five
Chemistry
2 answers:
Allisa [31]3 years ago
6 0

Hello,

Your question states: If an atom of nitrogen binds with three hydrogen atoms to form a molecule of ammonia, how many lone pairs of electrons does nitrogen have?

Your answer would be:

B. Three


Brainliest!?!


Hope this helps!


Have a great day:)


~Rendorforestmusic

Afina-wow [57]3 years ago
5 0

Answer:The correct answer is option A.

Explanation:

Nitrogen binds with 3 hydrogen atom to give ammonia .

N_2+3H_2\rightarrow 2NH_3

Electronic configuration of Nitrogen is given as:

[N]=1s^22s^22p^3

Nitrogen has 5 valence electrons and needs three electrons to complete its octet.

In ammonia molecule nitrogen atom accepts three electrons from each hydrogen atom.

Electron as lone pair = Valence electrons - Number of electrons in bonding

= 5 - 3 = 2 = 1 pair electrons as present as lone pair

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<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

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Equilibrium moles of ammonia = 0.100 moles

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For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

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K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

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Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

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Answer:

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