You can reason it out like this:
-- The car starts from rest, and goes 8 m/s faster every second.
-- After 30 seconds, it's going (30 x 8) = 240 m/s.
-- Its average speed during that 30 sec is (1/2) (0 + 240) = 120 m/s
-- Distance covered in 30 sec at an average speed of 120 m/s
= 3,600 meters .
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The formula that has all of this in it is the formula for
distance covered when accelerating from rest:
Distance = (1/2) · (acceleration) · (time)²
= (1/2) · (8 m/s²) · (30 sec)²
= (4 m/s²) · (900 sec²)
= 3600 meters.
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When you translate these numbers into units for which
we have an intuitive feeling, you find that this problem is
quite bogus, but entertaining nonetheless.
When the light turns green, Andy mashes the pedal to the metal
and covers almost 2.25 miles in 30 seconds.
How does he do that ?
By accelerating at 8 m/s². That's about 0.82 G !
He does zero to 60 mph in 3.4 seconds, and at the end
of the 30 seconds, he's moving at 534 mph !
He doesn't need to worry about getting a speeding ticket.
Police cars and helicopters can't go that fast, and his local
police department doesn't have a jet fighter plane to chase
cars with.
Answer:
All the objects experience the same acceleration
Explanation:
According to Newton's law of universal gravitation, we have the gravitational force F given by the relation;
Where;
G = The universal gravitational constant
M₁ = The mass of the Earth
m₂ = The mass of the object in the Earths gravitational field
R = The radius of the Earth
Therefore, we have;
Which gives;
Therefore, based on the above calculation, all three object will have the same acceleration due to gravity, g, when air resistance is ignored.
Answer:
Explanation:
From the equation we are told that:
Velocity of French sub
Velocity of U.S. sub at
French Wave Frequency
Velocity of wave
Generally the equation for Signal's frequency as detected by the U.S. is mathematically given by
Doppler effect
Answer:
a=8.06m/s^2
Explanation:
The box can be considered negligible body slidding down along a curved path defined by the parabola Y=Ax^2
Note:
When it's at A(x=2m, y=1.6m),
the speed Vb=8m/s and the increase in speed=4m/s^2
To find the acceleration,
Y=Ax^2
dy/dx=8x
d^2y/dx^2=8
p={[1+(dy/dx)^2]^3/2}/|d^2y/dx^2| .......1
substituting into 1, we have
p=8.39624m
an=v^2/p
an=8^2/8.39624=7.6224m/s^2
a=sqrt(at^2+an^2)
a=sqrt(4^2+7.62246^2)
a=8.06m/s^2