Answer:
The percent by mass of water in this crystal is:
Explanation:
This exercise can be easily solved using a simple rule of three where the initial weight of the hydrated crystal (6,235 g) is taken into account as 100% of the mass, and the percentage to which the mass of 4.90 g corresponds (after getting warm). First, the values and unknown variable are established:
- 6,235 g = 100%
- 4.90 g = X
And the value of the variable X is found:
- X = (4.90 g * 100%) / 6,235 g
- X = approximately 78.6%.
The calculated value is not yet the percentage of the water, since the water after heating the glass has evaporated, therefore, the remaining percentage must be taken, which can be calculated by subtraction:
- Water percentage = Total percentage - Percentage after heating.
- <u>Water percentage = 100% - 78.6% = 21.4%</u>
No, the properties of a substance are not affected by the amount of a substance.
Answer:
72.6% Error
Explanation:
% error = 
58.44 is the weight of NaCl
<u>Answer:</u> The value of 
is 0.136 and is reactant favored.
<u>Explanation:</u>
Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as 
For the chemical reaction between carbon monoxide and hydrogen follows the equation:
The expression for the is given as:
![K_{c}=\frac{[NH_3]^2}{[N_2][H_2]^3}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNH_3%5D%5E2%7D%7B%5BN_2%5D%5BH_2%5D%5E3%7D)
We are given:
![[NH_3]=0.25M](https://tex.z-dn.net/?f=%5BNH_3%5D%3D0.25M)
![[H_2]=0.75M](https://tex.z-dn.net/?f=%5BH_2%5D%3D0.75M)
![[N_2]=1.1M](https://tex.z-dn.net/?f=%5BN_2%5D%3D1.1M)
Putting values in above equation, we get:
There are 3 conditions:
- When
; the reaction is product favored. - When
; the reaction is reactant favored. - When
; the reaction is in equilibrium.
For the given reaction, the value of is less than 1. Thus, the reaction is reactant favored.
Hence, the value of is 0.136 and is reactant favored.
