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3 years ago

May someone help me with a few questions?

Chemistry

1 answer:

Gennadij [26K]3 years ago

5 0

Answer: again these are equations you should know; I hope you WILL LEARN them, and how to write your own; these must have come from the book or lecture, and I do not want to berate you, I want you to improve more every day. But it is very late here, and I must finally go. Study hard!

No matter what, study hard.

I loved research; tons of fun, meeting new people, and learning new things.

Hopefully many people here will also.

I bid you all a Good Night.

Explanation:

You might be interested in

Can you tell me name of Chemicals in food?

Artyom0805 [142]

Answer:

Guar gum

sodium nitrite

artificial food colorings

monosodium glutamate

etc

6 0

3 years ago

In the reaction BaCO3 + 2HNO3 + Ba(NO3)2 + CO2 + H2O, what mass of Ba(NO3)2 can be formed by combining 55 g BaCO3 and 26 g HNO3

Nataliya [291]

From the stoichiometry of the reaction, the mass of barium nitrate produced is 54.9 g.

<h3>Stoichiometry</h3>

The term stoichiometry refers to mass - volume relationships. Stoichiometry can be used to calculate the amount, mass or volume of reactants and products from the balanced reaction equation.

The equation of the reaction is written as follows;

BaCO3 + 2HNO3 ------> Ba(NO3)2 + CO2 + H2O

Number of moles of BaCO3 = 55 g/197.34 g/mol = 0.28 moles

Number of moles of HNO3 = 26 g/63.01 g/mol = 0.41 moles

From the reaction equation;

1 mole of BaCO3 reacts with 2 moles of HNO3

0.28 moles of BaCO3 reacts with 0.28 moles × 2 moles/1 mole = 0.56 moles

There is not enough HNO3 hence it is the limiting reactant.

Number of moles of Ba(NO3)2 produced is obtained from;

2 moles of HNO3 yields 1 mole of Ba(NO3)2

0.41 moles of HNO3 yields 0.41 moles × 1 mole/2 moles

= 0.21 moles of Ba(NO3)2

Mass of Ba(NO3)2 = 0.21 moles × 261.337 g/mol = 54.9 g

Learn more about stoichiometry: brainly.com/question/9743981

8 0

3 years ago

A flask holds 3.01 x 1023 molecules of carbon dioxide. The container is holding ________

sammy [17]

(B), because 1.0 moles would be 6.02 x 10^23 molecules. So you have half a mole.<span>
</span>

8 0

4 years ago

A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc

Elan Coil [88]

Answer:

a. Moles of $NaOH$ = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

Or,

$Moles =Molarity \times {Volume\ of\ the\ solution}$

Given :

For $NaOH$ :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of $NaOH$ :

$Moles=0.1052 \times {15.62\times 10^{-3}}\ moles$

Moles of $NaOH$ = 0.001643 moles

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains $\frac{0.296}{1.159}\times 1.213$ g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0

3 years ago

0.500 L of a gas is collected at 2911 MM and 0°C. What will the volume be at STP?

ioda

Answer:

V₂ = 1.92 L

Explanation:

Given data:

Initial volume = 0.500 L

Initial pressure =2911 mmHg (2911/760 = 3.83 atm)

Initial temperature = 0 °C (0 +273 = 273 K)

Final temperature = 273 K

Final volume = ?

Final pressure = 1 atm

Solution:

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

by putting values,

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 3.83 atm × 0.500 L × 273 K / 273 K × 1 atm

V₂ = 522.795 atm .L. K / 273 K.atm

V₂ = 1.92 L

4 0

3 years ago