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galina1969 [7]
3 years ago
5

Find the sum of the equations: 1/(x-2)+3/(x+3)=4/(x^2+x-6)​

Mathematics
1 answer:
uysha [10]3 years ago
4 0

Answer:

x= 7/4

<u />

   

Step-by-step explanation:

Find the LCM for x-2,x+3,x^2+x-6 which is (x-2) (x+3)

then multiply

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nata0808 [166]

Answer:

i believe the answer is 3^2(-2)^6/ 5^4

Step-by-step explanation:

6 0
1 year ago
PLEASE HELPPP!!!
Tatiana [17]

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ko iu whry frhf weoiy

Step-by-step explanation:

no sé cómo hacer esto lo siento

7 0
3 years ago
What is a rational number between 10.2 and 10.3
ycow [4]
Hola!

A rational number could range from 10.21 to 10.2001

Hope that helped :)
4 0
3 years ago
Read 2 more answers
10. Tom bought 3 pairs of socks and a shirt. The total cost was $21.00. The socks cost $2.50 for each pair. How much did the shi
Valentin [98]

Answer:

3x + y = 21

x = 2.5

7.5 + y = 21

y = 13.5

shirt cost $13.50

Step-by-step explanation:

6 0
2 years ago
The LB Company has long manufactured a light bulb with an average life of 5400 hours. Company researchers have recently develope
elena55 [62]
<h2><u>Answer with explanation</u>:</h2>

Let \mu be the average life of light bulbs.

As per given , we have

Null hypothesis : H_0 : \mu =5400

Alternative hypothesis : H_a : \mu >5400

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Formula for Test statistic : z=\dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overline{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=95,\ \overline{x}=5483\ \&\ \sigma=500, we have

z=\dfrac{5483-5400}{\dfrac{500}{\sqrt{95}}}=1.61796786124\approx1.6180

Using z-value table , Critical one-tailed test value for 0.06 significance level :

z_{0.06}=1.5548

 Decision : Since critical z value (1.5548) < test statistic (1.6180), so we reject the null hypothesis .

[We reject the null hypothesis when critical value is less than the test statistic value .]

Conclusion : We have enough evidence at 0.06 significance level to support the claim that the new filament yields a longer bulb life

8 0
3 years ago
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