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Andreyy89
2 years ago
11

13 If CDEF is a rhombus, find m FED.

Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

Answer:

36

Step-by-step explanation:

8x-20=5x+1

-5       -5

3x=-20+1

+20 +20

3x=21

3  3

x=7

8(7)-20

FED=36

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The sum of rational number and an irrational number
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The sum of a rational number and an irrational number is irrational." By definition, an irrational number in decimal form goes on forever without repeating (a non-repeating, non-terminating decimal). By definition, a rational number in decimal form either terminates or repeats.

Step-by-step explanation:

However, if the irrational parts of the numbers have a zero sum (cancel each other out), the sum will be rational. "The product of two irrational numbers is SOMETIMES irrational." Each time they assume the sum is rational; however, upon rearranging the terms of their equation, they get a contradiction (that an irrational number is equal to a rational number). Since the assumption that the sum of a rational and irrational number is rational leads to a contradiction, the sum must be irrational.

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What is x in 0x<3 i though you couldn't divide anything with 0
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Step-by-step explanation:

0x<3

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2 years ago
What can be used to show the difference in variation for two populations that have equivalent measures of center?.
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what is the quotient when x3 − 5x2 2x 5 is divided by x − 2? x2 − 3x − 4 x2 − 7x 16 x2 − 3x − 4 − 3 over the quantity of x minus
nekit [7.7K]
<span><u><em>The correct answer is: </em></u>
x</span>²<span>-3x-4 -</span>\frac{3}{x-2}<span>.

<u><em>Explanation</em></u><span><u><em>: </em></u>
To divide these polynomials, the dividend, x</span></span>³<span><span>-5x</span></span>²<span><span>+2x+5, goes under the box, and the divisor, x-2, goes outside of the box.

We first want to find what we multiply x by to make x</span></span>³<span><span>; x*x</span></span>²<span><span>=x</span></span>³<span><span>, so we write x</span></span>²<span><span> over -5x</span></span>²<span><span> in the box.
 
<u>Now we multiply our divisor, x-2, by x</u></span></span><u>²</u><span><span><u>: </u>
x*x</span></span>²<span><span>=x</span></span>³<span><span>
-2*x</span></span>²<span><span>=-2x</span></span>²<span><span>.

This goes under x</span></span>³<span><span>-5x</span></span>²<span><span> in the box.

<u>Now we subtract: </u>
(x</span></span>³<span><span>-5x</span></span>²<span><span>)-(x</span></span>³<span><span>-2x</span></span>²<span><span>)=-3x</span></span>²<span><span>.

This goes below the 2x</span></span>²<span><span> we wrote, and we bring down 2x.

Now we see what we multiply x by to make -3x</span></span>²<span><span>;
x*-3x=-3x</span></span>²<span><span>, so we write -3x beside x</span></span>²<span><span> in the quotient (at the top).

<u>We multiply our divisor, x-2, by -3x: </u>
 x*-3x=-3x</span></span>²
<span><span>-2*-3x=6x.

We write -3x</span></span>²<span><span>+6x under our -3x</span></span>²<span><span>+2x and <u>subtract</u>:
(-3x</span></span>²<span><span>+2x)-(-3x</span></span>²<span><span>+6x)=-4x.

Write this below 6x. Bring down +5.

Now we see what we multiply x by to make -4x;
x*-4=-4x, so write -4 beside -3x in the quotient.

<u>Multiply our divisor, x-2, by -4: </u>
x*-4=-4x;
-2*-4=8;

write -4x+8 below -4x+5 and <u>subtract:</u>
(-4x+5)-(-4x+8)=-3.

This gives us the quotient x</span></span>²<span><span>-3x-4 with a remainder of -3, so we write our full answer as x</span></span>²<span><span>-3x-4-(3/x-2).</span></span>
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3 years ago
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