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Andreyy89
3 years ago
11

13 If CDEF is a rhombus, find m FED.

Mathematics
1 answer:
Tatiana [17]3 years ago
8 0

Answer:

36

Step-by-step explanation:

8x-20=5x+1

-5       -5

3x=-20+1

+20 +20

3x=21

3  3

x=7

8(7)-20

FED=36

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James, Priya, and Siobhan work in a grocery store. James makes
Ulleksa [173]
<span>If Priya makes 20% more than James and Siobhan makes 15% less than Priya, then it follows that Priya makes 85% of 120% of James' hourly wage. Which is to say that Siobhan makes 85% of $9.60 per hour. Since 85% of $9.60 is $8.16, this means that Siobhan makes $8.16 an hour.</span>
5 0
4 years ago
If f(x) = 5x + 40, what is f(x) when x = –5? –9 –8 7 15
Bogdan [553]

Answer:

15

Step-by-step explanation:

5(-5) + 40 = -25 + 40 = 15

3 0
3 years ago
State the value of the discriminant. Then determine the number of real roots of the equation. n(7n + 8) = –10
Viktor [21]

Answer:

  a.  -216, 0 real roots

Step-by-step explanation:

The discriminant of ...

  ax² + bx + c = 0

is ...

  d = b² -4ac

When we put your equation into the standard form shown above, we get ...

  7n² +8n +10 = 0

Then we can identify a=7, b=8, c=10. The discriminant is then ...

  d = 8² - 4·7·10 = 64 -280 = -216

___

The interpretation of the discriminant is ...

  • < 0; no real roots (2 complex roots)
  • = 0; one real root (multiplicity 2)
  • > 0; 2 real roots

Your discriminant is -216, so there are 0 real roots.

7 0
3 years ago
6) y = -5(x + 7)<br> Is it linear
Firdavs [7]

Answer:yes

Step-by-step explanation:

It has the y=mx+b format

5 0
3 years ago
Can somebody number the problem and work it out for me thanks and btw it’s solving system by graphics
adoni [48]

Answer:

Solutions are (3,1) and (4,2)

Step-by-step explanation:

Graph is shown in the attached sheet

Given are two systems of equations and we have to solve them using graph

For graphing let us first prepare table for x and y.

1) y=\frac{-2x}{3} +3:\\y=2x-5

I line                                                             II line

x     0   4.5    3                              x       0      2.5     3

y      3   0       1                              y       -5      0        1

The two lines intersect at (3,1)

Hence solution is (3,1)

--------------------------------------------

2) y=\frac{x}{2} \\-6x+3y=-18

I line                                                             II line

x     0    2    4                              x       0      6     4

y      0   1      2                             y       3      0     2

The two lines intersect at (4,2)

Hence solution is (4,2)

3 0
3 years ago
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