14m/s
Explanation:
Given parameters:
Height of the ball = 10m
Unknown:
Velocity of fall or final velocity = ?
Solution:
We are going to use the appropriate equation of motion to solve this problem.
The object is falling with respect to gravity.
V² = U² + 2gH
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity 9.8m/s²
H is the height of fall
The initial velocity here is zero and
V² = 2 x 9.8 x 10 = 196
V = 14m/s
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Motion problems brainly.com/question/5248528
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No answer is possible until we know the number that belongs after the words "... angular speed of ".
Answer:
Every electric circuit in a wiring system must be protected against overloads. A circuit overload occurs when the amount of current flowing through the circuit exceeds the rating of the protective devices. The amount of current flowing in a circuit is determined by the load -- or the "demand" -- for current.
Explanation:
Hope this helps :)
Answer:
A) a = 73.304 rad/s²
B) Δθ = 3665.2 rad
Explanation:
A) From Newton's first equation of motion, we can say that;
a = (ω - ω_o)/t. We are given that the centrifuge spins at a maximum rate of 7000rpm.
Let's convert to rad/s = 7000 × 2π/60 = 733.04 rad/s
Thus change in angular velocity = (ω - ω_o) = 733.04 - 0 = 733.04 rad/s
We are given; t = 10 s
Thus;
a = 733.04/10
a = 73.304 rad/s²
B) From Newton's third equation of motion, we can say that;
ω² = ω_o² + 2aΔθ
Where Δθ is angular displacement
Making Δθ the subject;
Δθ = (ω² - ω_o²)/2a
At this point, ω = 0 rad/s while ω_o = 733.04 rad/s
Thus;
Δθ = (0² - 733.04²)/(2 × 73.304)
Δθ = -537347.6416/146.608
Δθ = - 3665.2 rad
We will take the absolute value.
Thus, Δθ = 3665.2 rad
