Answer:
![n = 115*0.80= 92](https://tex.z-dn.net/?f=%20n%20%3D%20115%2A0.80%3D%2092)
Then the estimation for the number of female members who areover 50 years of age is 92
Step-by-step explanation:
For this problem we know that the total number of members in a social club is 115, And we also know that 80 %of the members who are over 50 yearsold are femaleIn order to find the number of female member who are over 50 yaers we can do this operation:
![n = 115*0.80= 92](https://tex.z-dn.net/?f=%20n%20%3D%20115%2A0.80%3D%2092)
Then the estimation for the number of female members who areover 50 years of age is 92
Answer:
WhAt where is the rest if this is it than wow
Step-by-step explanation:
Answer:
0.014 or 1.4% of connectors fail during the warranty period.
Step-by-step explanation:
Consider the provided information.
Let: D = electrical connector is dry
D' = electrical connector is not kept dry (i.e., is wet)
F = connector fails during warranty period
F' = connector does not fail during warranty period
90% of the connectors are kept dry
That means P(D)=0.9
10% are wet,
P(D')=0.1
The probability is 1% that an electrical connector that is kept dry fails during the warranty period, i.e.
P(F|D)=0.01
If the connector is ever wet, the probability of a failure during the warranty period is 5%, i.e.
P(F|D')=0.05
![P(F)=P(D)\times P(F|D)+P(D')\times P(F|D')\\P(F)=0.9\times 0.01+0.1\times 0.05\\P(F)=0.014](https://tex.z-dn.net/?f=P%28F%29%3DP%28D%29%5Ctimes%20P%28F%7CD%29%2BP%28D%27%29%5Ctimes%20P%28F%7CD%27%29%5C%5CP%28F%29%3D0.9%5Ctimes%200.01%2B0.1%5Ctimes%200.05%5C%5CP%28F%29%3D0.014)
Hence, 0.014 or 1.4% of connectors fail during the warranty period.
Answer:
256 and 14, 24, 16, 18
Step-by-step explanation:
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