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3 years ago

10

Free brainliest for first person

2 answers:

dangina [55]3 years ago

6 0

Answer:

im here wowowowow

Step-by-step explanation:

astraxan [27]3 years ago

3 0

Answer:

Hey I know im not frist but still :)

Step-by-step explanation:

Have a good day

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cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

4 0

3 years ago

What are 3 consecutive numbers that is the sum of -27.please be right.use odd numbers

qaws [65]

You're asking for three consecutive odd numbers, then
Let, the numbers = x, x+2, x+4

It is given that, x + x+2+ x+4 = -27
3x + 6 = -27
3x = -27 - 6
x = -33/3
x = -11
Then, x+2 = -9 & x+4 = -7

In short, Your Numbers would be: -7, -9,-11

Hope this helps!

6 0

3 years ago

When you solve an equation and you end with a TRUE STATEMENT, the solution set will be:

Stella [2.4K]

Answer:

false

Step-by-step explanation:

7 0

3 years ago

Which logarithmic equation is equivalent to the exponential equation below?

aleksandr82 [10.1K]

Option B: $\ln 6=5 x$ is the correct answer.

Explanation:

The exponential equation is $e^{5 x}=6$

If $f(x)=g(x)$ , then $\ln (f(x))=\ln (g(x))$

Thus, the equation becomes

$\ln \left(e^{5 x}\right)=\ln (6)$

Applying log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ and thus the equation becomes

$5 x \ln (e)=\ln (6)$

Since, we know that, $\ln (e)=1$ , using this we get,

$5 x=\ln (6)$

Hence, the logarithmic equation which is equivalent to the exponential equation $e^{5 x}=6$ is $\ln 6=5 x$

Thus, Option B is the correct answer.

7 0

3 years ago

F(x) = -3x+17 and g(x) = x^2 -6 find g(5)-f(5)

aniked [119]

Answer:

For the given functions, the value of g(5)-f(5) = 17

Step-by-step explanation:

Here, the given functions are:

f(x) = -3x + 17

$g(x) = x ^2 - 6$

So, f(5) = -3(5) + 17

= -15 + 17 = 2

And $g(5) = (5)^2 - 6 = 25 - 6 = 19$

So, f(5) = 2 and g(5) = 19

⇒g(5) - f(5) = 19 - 2 = 17

Hence, for the given functions, the value of g(5)-f(5) = 17

3 0

3 years ago