SOMEONE PLEASE HELP‼️‼️‼️ ILL MARK BRAINLYEST PLEASE ‼️‼️
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The standard equation of a circle with centre (xc,yc) and radius R is given by
Substituting
centre (xc,yc) = (4,-3)
R=2.5
The equation is therefore
or
(x-4)^2+(y+3)^2=6.25
Substituting
centre (xc,yc) = (4,-3)
R=2.5
The equation is therefore
(x-4)^2+(y+3)^2=6.25
In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.
