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kompoz [17]
3 years ago
5

An atom of argon in the ground state tends not to bond with an atom of a different element because the argon atom has (a)a total

of two valence electrons (b)more protons than neutrons (c)more neutrons than protons or (d)a total of eight valence electrons
Chemistry
2 answers:
bezimeni [28]3 years ago
7 0

Answer: Option (d) is the correct answer.

Explanation:

Atomic number of argon is 18 and its electronic configuration is 1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}.

Also, it is known that number of electrons in K, L and M shells of argon are 2, 8, 8.

Thus, we can conclude that an atom of argon in the ground state tends not to bond with an atom of a different element because the argon atom has a total of eight valence electrons.

So, as per the octet rule, last sub-shell of argon is completely filled. Hence, it will not form any bond with any other atom.

Dvinal [7]3 years ago
5 0
The answer is <span>a total of eight valence electrons
hope this help
</span>
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In ClO2-, oxygen contains 8 electrons in its valence shell and oxygen will share one electron with chlorine to complete the octet of Cl. In other four, we can clearly see that there are more or less than 8 electrons in the outer shell of oxygen so we can clearly say that ClO, ClO3-, ClO- and ClO4-  are disobeying the octet rule.

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