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n200080 [17]
3 years ago
8

You can shift weight to the front of your vehicle by __________ .

Chemistry
2 answers:
Flura [38]3 years ago
6 0

We can change or shift vehicle weight by

a) change in speed  (by accelerating and by braking)

b) change in direction (turning left or right)

Now there is a physics behind the shift in weight based on braking and accelerating.

You can shift weight to the front of your vehicle by braking.

Similarly, we can shift weight to back by accelerating.

Bending or turning left will transfer weight to right

Bending or turning right will transfer weight to left

poizon [28]3 years ago
3 0
C. Accelerating should be the correct onw
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Collision of which two types of plates create the deepest earthquakes? Why do you think this is?
Elis [28]

Answer:

The collision of oceanic plates and any other plates in which the oceanic plate slides beneath the other plate creates the biggest earth quakes. Most of these earth quakes occur beneath the sea or oceans and can cause volcanic eruptions as well. Tsunami is another oceanic event that occurs due to earth quakes occurring due to shifting of plates beneath the sea.

7 0
3 years ago
The standard free energy of formation, ΔG∘f, of a substance is the free energy change for the formation of one mole of the subst
OLEGan [10]

Answer:

B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG∘f=−451.0 kJ/mol

D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol

Explanation:

The spontaneity of a reaction  is given by the value of the standard Gibbs free energy of the reaction (ΔG°rxn). The more negative is the ΔG°rxn, the more spontaneous is a reaction.

The ΔG°rxn can be calculated using the following expression:

ΔG°rxn = ∑np × ΔG°f(products) − ∑nr × ΔG°f(reactants)

By definition, the standard Gibbs free energy of formation of simple substances in their most stable state is zero. That is why, in the reaction of formation of a compound ΔG°rxn = ΔG°f(product).

<em>Based on the standard free energies of formation, which of the following reactions represent a feasible way to synthesize the product? </em>

<em>     A. N₂(g) + H₂(g) → N₂H₄(g); ΔG°f=159.3 kJ/mol. </em>

<em>     </em>Not feasible. ΔG°rxn = ΔG°f(product) > 0.

    <em>B. 2 Na(s) + O₂(g) → Na₂O₂(s); ΔG°f=−451.0 kJ/mol</em>

    Feasible. ΔG°rxn = ΔG°f(product) < 0.

    <em>C. 2 C(s) + 2 H₂(g) → C₂H₄(g); ΔG°f=68.20 kJ/mol</em>

    Not feasible. ΔG°rxn = ΔG°f(product) > 0.

    <em>D. 2 SO(g) + O₂(g) → 2 SO₂(g); ΔG°f=−600.4 kJ/mol</em>

    Feasible. ΔG°rxn = ΔG°f(product) < 0.

3 0
3 years ago
Calculate the number of mol of S by 1.81
rodikova [14]
It’s 6.022x10^23. This is how many atoms of any element are in one mole of that element. No matter what it is, there are always 6.022x10^23 atoms per mole. So divide 1.81x10^24 by 6.022x10^23 to get approximately 3 moles of sulfur.
5 0
3 years ago
Find [H+] of a 0.056 M hydrofluoric acid solution. Ka = 1.45 x 10-7
brilliants [131]

Answer:  [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

Explanation:

HF\rightarrow H^+F^-

 cM              0             0

c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 0.056 M and \alpha = ?

K_a=1.45\times 10^{-7}

Putting in the values we get:

1.45\times 10^{-7}=\frac{(0.056\times \alpha)^2}{(0.056-0.056\times \alpha)}

(\alpha)=0.0016

[H^+]=c\times \alpha

[H^+]=0.056\times 0.0016=8.96\times 10^{-5}  

Thus [H^+] of 0.056 M HF solution is 8.96\times 10^{-5}

8 0
3 years ago
Which coefficients correctly balance the formula equation nh4no2(s)-&gt; n2(g) + h2o(l)?
horrorfan [7]
NH4NO2 > N2 + 2 H2O
8 0
3 years ago
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