Answer:
A. relative humidity B. air temperature C. air pressure D. atmospheric
Explanation:
I believe the answer is option B. The bonded pair of valence electrons are shown using circles
Some possible public policies aimed at reducing the amount of carbon dioxide in the air is that companies should make use of new emissions technology to avoid air pollution.
<h3>
What is air pollution?</h3>
What is air pollution?Air pollution is the release of substance that are dangerous or harmful to human health into the environment.
Excessive release of carbon dioxide into the atmosphere causes pollution and deplete our ozone layer.
One of the policy government have out in check is that all companies should purchase or make use of new emissions technology to avoid polluting the environment and causing harm to human health.
Therefore, some possible public policies aimed at reducing the amount of carbon dioxide in the air is that companies should make use of new emissions technology to avoid air pollution.
Learn more on air pollution here,
brainly.com/question/10004402
Answer:
15.4%
Explanation:
If Ka = 0.54 mM = 1.51x10⁻⁵
Then;
C₄H₈O₂ --------> C₄H₇O₂⁻ + H⁺
I 0.54x10⁻³ 0 0
E 0.54x10⁻³(1-x) 0.54x10⁻³x 0.54x10⁻³x
Recall that x is the percentage degree of dissociation
From the ICE table;
Ka = [C₄H₇O₂⁻] [ H⁺]/[C₄H₈O₂]
1.51x10⁻⁵=(0.54x10⁻³x) (0.54x10⁻³x)/ 0.54x10⁻³(1-x)
1.51x10⁻⁵ = 0.54x10⁻³x^2/1-x
1.51x10⁻⁵(1-x) = 0.54x10⁻³x^2
1.51x10⁻⁵ - 1.51x10⁻⁵x = 0.54x10⁻³x^2
Hence;
0.54x10⁻³x^2 + 1.51x10⁻⁵x - 1.51x10⁻⁵=0
x^2 + 0.028x - 0.028 = 0
Solving the quadratic equation here;
x = 0.154 or −0.182
Ignoring the negative result, x = 0.154
Hence, fraction of butanoic acid that is in the dissociated form in this solution = 15.4%
Answer:
Oxygen is in excess.
Explanation:
The coefficients of the balanced equation create a mole ratio that shows the ratio of how many reactants are used up and products are created.
The mole ratio of Mg to O2 in this equation is 2:1, which means that for every two moles of Mg used, there will be 1 mole of O2 used.
If we have 3.00 moles of Mg, we will only need 1.5 moles of oxygen to completely burn the Mg. Therefore, when all 3.00 moles of Mg are used, there will still be some of the 2.20 moles of oxygen remaining.
