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Leokris [45]
2 years ago
12

A square window has an area of x2 – 14x + 49 square feet. Find the length of one side of the square.

Mathematics
2 answers:
Irina18 [472]2 years ago
8 0

Answer:

_D__

Step-by-step explanation:

HOPE THIS helpsss you III

Lyrx [107]2 years ago
7 0

Answer:

Step-by-step explanation:

(x - 7)² = x² - 14x + 49

so each side is x - 7 long where x ≠ 7

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Answer 565

Step-by-step explanation:

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3 years ago
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Write the five term sequence that would represent each recursive rule f(x) = f(x-1) -7; f(2) = 12
barxatty [35]

<u>Answer: </u>

Required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

<u> Solution: </u>

Need to find the five terms of the sequence.

Given recursive rule is f(x) = f(x-1) -7

Substituting x = 2 , f(2) = f(2-1)-7

= f(2) = f(1) – 7    ------(1)

Also given that f(2) = 12.  

On substituting the given value of f(2) in eq (1) we get

12 = f(1) – 7

f(1) = 12 + 7 = 19

Using given recursive rule and given value of f(2) calculating f(3)

Substituting x = 3 ,  

f(3) = f(3-1) – 7  

= f(2) – 7  

= 12 – 7  

= 5

Using given recursive rule and calculated  value of f(3) calculating f(4)

Substituting x = 4,  

f(4) = f(4-1) – 7  

= f(3) – 7  

= 5– 7  

= -2

Using given recursive rule and calculated  value of f(4) calculating f(5)

Substituting x = 5,  

f(5) = f(5-1) – 7  

= f(4) – 7  

= -2– 7  

= -9

Hence required five terms of sequence are 19 , 12 , 5 , -2 and -9 .

8 0
4 years ago
$84 increased by 120 percent
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8x100=8x10 to the second power?
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3 years ago
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Expand the binomial<br> <img src="https://tex.z-dn.net/?f=%28x-%5Cfrac%7B2%7D%7B5%7D%29%5E%7B2%7D" id="TexFormula1" title="(x-\f
kkurt [141]

Answer:

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

Step-by-step explanation:

You have two methods to expand this binomial.

Method 1  

If you have the expression:

(x- \frac{2}{5})^{2}

You can write the expression it in the following way:

(x-\frac{2}{5})^{2}=(x-\frac{2}{5})(x-\frac{2}{5})

Then, apply the distributive property:

(x-\frac{2}{5})(x-\frac{2}{5}) = x^2 -\frac{2}{5}x -\frac{2}{5}x+ (\frac{2}{5})\frac{2}{5}

Simplify the expression:

(x-\frac{2}{5})^2= x^2 -\frac{4}{5}x+ (\frac{4}{25})

---------------------------------------------------------------------------------------

Method 2

For any expression of the form:

(a-b)^2

Its expanded form will be:

(a-b)^2= a^2 -2ab + b^2

If

a = x

b =\frac{2}{5}

(x- \frac{2}{5})^{2} = x^2 - 2x\frac{2}{5} + (\frac{2}{5})^2

(x- \frac{2}{5})^{2} = x^2 -\frac{4}{5}x + \frac{4}{25}

3 0
3 years ago
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