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Lena [83]
2 years ago
14

Help FAST PLZ!!! marking brainliest!

Mathematics
1 answer:
ss7ja [257]2 years ago
5 0

Answer:

After finding the prime factorization of $2010=2\cdot3\cdot5\cdot67$, divide $5300$ by $67$ and add $5300$ divided by $67^2$ in order to find the total number of multiples of $67$ between $2$ and $5300$. $\lfloor\frac{5300}{67}\rfloor+\lfloor\frac{5300}{67^2}\rfloor=80$ Since $71$,$73$, and $79$ are prime numbers greater than $67$ and less than or equal to $80$, subtract $3$ from $80$ to get the answer $80-3=\boxed{77}\Rightarrow\boxed{D}$.

Step-by-step explanation:

hope this helps

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Answer A, B, C, Please, and Thanks!
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11+m>15 what’s the answer for this problem?
hjlf

Answer:

m > 4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

11 + m > 15

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Subtract 11 on both sides:                    m > 4

Here we see that any value <em>m</em> greater than 4 would work as a solution to the inequality.

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