f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
A picture
Step-by-step explanation:
Answer:
m∠ACB = 82°
Step-by-step explanation:
m∠ACB = 180° - m∠ACD
∠ACB and ∠ACD are supplementary, which add up to 180°
m∠ACB = 180° - 98°
m∠ACB = 82°
-Chetan K
A² + b² = c²
8² + x² = 16²
x² = 16² - 8²
x² = 192
x =√192
x =8√3
