Box has all sides same leinght(a). Area of that box is 6*a^2.
Cost of material for bottom and 4 sides is 2$/ft^2. Area of bottom and sides is A=5*a^2
Cost of material for top is 4$/ft^2. Area of top of the box is T=a^2
A*2+T*4=72
5*a^2*2+a^2*4=72
a^2*(10+4)=72
a^2*14=72, a^2=72/14, a=root(72/14), a=2.267ft
Dimensions of the box: leinght of sides 2.2ft. Area of hole box 30.835ft^2
Area of the bottom and sides: A=5*a^2=25.696ft^2
Area of the top : T=a^2=5.139ft^2
Check: A*2$+T*4$=71.95$
If a coin is dropped at a relatively low altitude, it's acceleration remains constant. However, if the coin is dropped at a very high altitude, air resistance will have a significant effect. The initial acceleration of the coin will be the greatest. As it falls down, air resistance will counteract the weight of the coin. So, the acceleration will decrease. Although the acceleration decreases, the coin still accelerates, that is why it falls faster. When the air resistance fully counters the weight of the coin, the acceleration will become zero and the coin will fall at a constant speed (terminal velocity). So, the answer should be, The acceleration decreases until it reaches 0. The closest answer is.
a. The acceleration decreases.
297.729km :-) hope this helps
Yes I can help jus tell me what the 26th question is
