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Pie
3 years ago
13

When will electric charges flow?

Physics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

A

Explanation:

Norma-Jean [14]3 years ago
7 0
C. when the circuit is closed
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Is Heredity nature or nurture?
Luden [163]
The answer is nature
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3 years ago
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If an ice skater with a mass of 50 kg was accelerating at 10 m/s and is on her way to hit a
IrinaK [193]

500N

Explanation:

Given parameters:

Mass of skater = 50kg

Acceleration = 10m/s

Unknown:

Force  = ?

Solution;

Force is a push or pull on a body. it is given as the product of mass and acceleration:

               Force = mass x acceleration

    Input the parameters:

                  Force = 50 x 10 = 500N

She hits the wall with a force of 500N

Learn more:

Force brainly.com/question/3820012

#learnwithBrainly

5 0
3 years ago
A 3.06kg stone is dropped from a height of 10.0m and strikes the ground with a velocity of 7.00m/s. What average force of air fr
xxTIMURxx [149]
<span>22.5 newtons. First, let's determine how much energy the stone had at the moment of impact. Kinetic energy is expressed as: E = 0.5mv^2 where E = Energy m = mass v = velocity Substituting known values and solving gives: E = 0.5 3.06 kg (7 m/s)^2 E = 1.53 kg 49 m^2/s^2 E = 74.97 kg*m^2/s^2 Now ignoring air resistance, how much energy should the rock have had? We have a 3.06 kg moving over a distance of 10.0 m under a force of 9.8 m/s^2. So 3.06 kg * 10.0 m * 9.8 m/s^2 = 299.88 kg*m^2/s^2 So without air friction, we would have had 299.88 Joules of energy, but due to air friction we only have 74.97 Joules. The loss of energy is 299.88 J - 74.97 J = 224.91 J So we can claim that 224.91 Joules of work was performed over a distance of 10 meters. So let's do the division. 224.91 J / 10 m = 224.91 kg*m^2/s^2 / 10 m = 22.491 kg*m/s^2 = 22.491 N Rounding to 3 significant figures gives an average force of 22.5 newtons.</span>
3 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 167 cm, but its circumference is decreasing at a constant
Kisachek [45]

Answer:

Part a)

EMF = 5.6 \times 10^{-3} V

Part b)

Since the radius is decreasing so induced current will increase the flux through the coil

So it would be clockwise in direction

Explanation:

As we know that magnetic flux linked with the coil is given as

\phi = \pi r^2 B

now the rate of change in flux is given as

\frac{d\phi}{dt} = 2\pi r \frac{dr}{dt} B

now we know that circumference is decreasing at rate of 15 cm/s

so here we know the length of circumference as

C = 2\pi r

So rate of change in circumference is

\frac{dC}{dt} = 2\pi \frac{dr}{dt}

\frac{1}{2\pi}(15 cm) = \frac{dr}{dt}

final length of circumference at t = 8 s

C = 167 - (15)(8) = 47

Part a)

Now the induced EMF is given as

EMF = (2\pi r)(\frac{1}{2\pi})(0.15)(0.5)

EMF = (0.47)(\frac{1}{2\pi})(0.15)(0.5)

EMF = 5.6 \times 10^{-3} V

Part b)

Since the radius is decreasing so induced current will increase the flux through the coil

So it would be clockwise in direction

5 0
3 years ago
Una bombilla de incandescencia tiene un filamento de wolframio cuya resistividad es de 5,6 por 10 a la -8 m , su longitud es de
Amanda [17]

Answer:

  R = 0.14  Ω

Explanation:

The resistance of a metal is given by the relation

         R = \rho \frac{L}{A}

where ρ the resistivity is 5.6 10-8 Ω m, they also give the length and the cross section (area)

Let's reduce the magnitudes to the SI system

        L = 200cm (1m / 100cm) = 2.00m

        A = 8.0 10⁻⁷ m²

let's calculate

       R = 5.6 10⁻⁸  \frac{2.00}{8.0  \ 10^{-7} }

       R = 1.4 10⁻¹ Ω

       R = 0.14  Ω

5 0
3 years ago
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