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Schach [20]
3 years ago
8

If kinetic energy is tripled what happens to centripetal acceleration.

Physics
1 answer:
Bas_tet [7]3 years ago
6 0

Answer:

Triples

Explanation:

Kinetic energy =1/2 mv^2 + 1/2 Iw^2

v= linear velocity

w= angular velocity

I= moment of inertia of object

I = k mr^2 where k is a constant for a particular shaped object

v = rw

w=v/r

Rotational Kinetic energy = 1/2 k m× (v/r)^2 × r^2

Total Kinetic energy = translational Kinetic energy + rotational Kinetic energy

KE = 1/2 (1+k) mv^2

Centripetal acceleration = mv^2/r

When KE is tripled, because 1/2(1+k) is a constant for a particular object, mv^2 part gets tripled. r doesn't appear in the equation of total Kinetic energy. So tripling Kinetic energy doesn't affect r. Therefore centripetal acceleration also gets tripled.

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Topic: Chapter 10: Projectory or trajectile?
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The other angle is 75⁰

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Given;

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R = \frac{u^2sin(2\theta)}{g}

To find another angle of projection to give the same range;

5.1 = \frac{10^2 sin(2\theta)}{9.81} \\\\100sin(2\theta) = 50\\\\sin(2\theta) = 0.5\\\\2\theta = sin^{-1}(0.5)\\\\2\theta = 30^0\\\\\theta = 15^0\\\\since \ the \ angle \ occurs \ in \ \ the \ first \ quadrant,\  the \ equivalent \ angle \\ is \ calculated \ as;\\\\90- \theta = 15^0\\\\\theta = 90 - 15^0\\\\\theta = 75^0

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