Hi 崩歲教行座難歲匕該雞看種崖還出葩來源不明就里說賣還幽人
The temperature of the water and copper beaker be together is 29.6⁰C.
<h3>
What is the equilibrium temperature of both substance?</h3>
The final temperature or equilibrium temperature of the water and copper beaker is calculated by applying the principle of conservation of energy.
Heat lost by the water = Heat gained by the copper beaker
mcΔθ (water) = mcΔθ (copper)
where;
- m is mass
- c is specific heat capacity
- Δθ is change in temperature
m₁c₁(T₁ - T) = m₂c₂(T - T₂)
where;
- T₁ is the initial temperature of water
- T₂ is the initial temperature of copper beaker
- T is the equilibrium temperature
Specific heat capacity of copper, c₂ = 389 J/kgK
Specific heat capacity of water , c₁ = 4200 J/kgK
(2)(4200)(30 - T) = (1)(389)(T - 20)
252,000 - 8400T = 389T - 7780
259,780 = 8789T
T = 259,780 /8789
T = 29.6⁰C
Learn more about equilibrium temperature here: brainly.com/question/8925446
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The equation you need to use is
where Q is the charge in C, I is the current in Amps and T is the time in seconds.
So we have T = 60s
I =
A
let's work out Q
C
this is the total charge passing a point in a minute so divide by the charge of one electron (
) to find the number of electrons passing the point in a minute which equals
Answer:
The speed of the raft is 1.05 m/s
Explanation:
The equation for the position of the stone is as follows:
y = y0 + v0 · t + 1/2 · g · t²
Where:
y = height of the stone at time t
y0 = initial height
v0 = initial speed
t = time
g = acceleration due to gravity
The equation for the position of the raft is as follows:
x = x0 + v · t
Where:
x = position of the raft at time t
x0 = initial position
v = velocity
t = time
To find the speed of the raft, we have to know how much time the raft traveled until the stone reached the river. For that, we can calculate the time of free fall of the stone:
y = y0 + v0 · t + 1/2 · g · t² (v0=0 because the stone is dropped from rest)
If we place the origin of the frame of reference at the river below the bridge:
0 m = 95.6 m - 9.8 m/s² · t²
-95.6 m / -9,8 m/s² = t²
t = 3.12 s
We know that the raft traveled (4.84 m - 1.56 m) 3.28 m in that time, then the velocity of the raft will be:
x/t = v
3.28 m / 3.12 s = v
v = 1.05 m/s