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vovangra [49]
3 years ago
6

Now assume that Alice and Bob are twins, and Alice left Earth and Bob stayed behind fixing his spaceship. If Alice spent some ti

me moving near the speed of light before returning to Earth, which statement is correct when Alice returns to Earth
Physics
1 answer:
alexgriva [62]3 years ago
8 0
我們的確認為我可以幫你們解決問題,我們要不要買不起房屋貸款土地
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A uniform continuous line charge with net positive charge Q and length L lies on the x-axis from −L2 to +L2. This problem asks a
irakobra [83]

Answer:

(C) zero (there is no net horizontal component of the E-field)

Explanation:

If we subdivide the bar into small pieces, each piece (dx) contains a charge (dq), the electric field of each piece is equivalent to the field of a punctual electric charge, and has a direction as shown in the attached figure. For each piece (dx) in the negative axis there is another symmetric piece (dx) in the positive axis, and as we see in the figure for symmetry the sum of their electric fields gives a resultant in the Y axis (because its components in X are cancelled by symmetry).

Then the resultant of the electric field will be only in Y.

(C) zero (there is no net horizontal component of the E-field)

5 0
3 years ago
A machine: A- Makes work easier to do
Vlad1618 [11]

A: makes work easier to do.

5 0
3 years ago
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A car horn emits a frequency of 400 Hz. A car traveling at 20.0 m/s sounds the horn as it approaches a stationary pedestrian. Wh
Temka [501]

Answer:

The observed frequency by the pedestrian is 424 Hz.

Explanation:

Given;

frequency of the source, Fs = 400 Hz

speed of the car as it approaches the stationary observer, Vs = 20 m/s

Based on Doppler effect, as the car the approaches the stationary observer, the observed frequency will be higher than the transmitted (source) frequency because of decrease in distance between the car and the observer.

The observed frequency is calculated as;

F_s = F_o [\frac{v}{v_s + v} ] \\\\

where;

F₀ is the observed frequency

v is the speed of sound in air = 340 m/s

F_s = F_o [\frac{v}{v_s + v} ] \\\\400 = F_o [\frac{340}{20 + 340} ] \\\\400 = F_o (0.9444) \\\\F_o = \frac{400}{0.9444} \\\\F_o = 423.55 \ Hz \\

F₀ ≅ 424 Hz.

Therefore, the observed frequency by the pedestrian is 424 Hz.

8 0
3 years ago
Most of the world uses fossil fuels because they are
Tasya [4]

They are easy to use and more reliable

8 0
3 years ago
At what temperature, in degrees Celsius, is the speed of sound in air 339 m/s?
coldgirl [10]

Answer: the answer would be C.

Explanation: hope this helps sorry if I got it wrong.

3 0
2 years ago
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