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Brums [2.3K]
3 years ago
9

Sound travels about 750 miles per hour. if you stand in a canyon and sound a horn, you will hear an echo. suppose it takes about

3.5 seconds to hear the echo. how far away is the canyon wall, in feet
Physics
2 answers:
diamong [38]3 years ago
5 0
The answer to this question would be:3850ft

To answer this question, you need to convert the speed velocity from miles/hour into feet/second. The equation would be: 750 miles/hour x 5280 foot/mile x 1 hour/3600second = 1100 ft/s
Then multiply the time with the velocity= 3.5 second x 1100 ft/s= 3850ft
umka21 [38]3 years ago
3 0

The canyon is 3.8 ×10³ feet if the echo is heard after 3.5 seconds.

Further Explanation

Speed is how fast an object moves or how far an object travels per unit time. If the distance traveled and the total time of travel are known, the speed can be calculated using the formula:

speed = \frac{distance}{time}

In the problem, we are given:

  • speed = 750 mi/h
  • time = 3.5 seconds

We are looking for the distance traveled by sound which can be represented by the variable <em>d.</em>

We can solve for d by manipulating the speed formula to get the equation:

distance \ (d) \ = speed \times time

But before we can plug in the given into the formula, the speed must be converted in terms of seconds since the given time is also in seconds:

speed \ = \frac{750 \ mi}{1 \ h} \times \frac{1 \ h}{60 min} \times \frac{1 \ min}{60 sec}\\\\\boxed {speed = 0.2083 \ \frac{mi}{sec}}

Now that the speed in miles per second is known, the distance can now be calculated using the formula above:

distance \ = speed \times \ time\\distance \ = 0.2083 \frac{mi}{sec} \times 3.5 sec\\\boxed {distance = 0.729 \ mi/tex]Now, since the problem requires the distance in feet, the conversion factor is used: 1 mi = 5280 ft[tex]0.729 mi \times \frac{5280 \ ft}{1 \ mi} = \boxed {3,849.12 \ ft}\\

Since the given has two significant digits, the answer must also have two. Therefore, the final answer must be 3.8 × 10³ feet.

<h3>LEARN MORE</h3>
  • Learn more about Velocity brainly.com/question/862972
  • Learn more about Acceleration brainly.com/question/4134594
  • Learn more about Distance - Time Graphs brainly.com/question/1378025

Keywords: speed, distsance, time

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Answer:

x=0.478\ m is the compression in the spring

Explanation:

Given:

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<u>Now since the bullet-mass gets embed into the block, we apply the conservation of momentum as:</u>

m.u=(M+m).v

0.01\times 300=(2+0.01)\times v

v=1.4925\ m.s^{-1}

Now this kinetic energy of the combined mass gets converted into potential energy of the spring.

\rm Kinetic\ energy=Spring\ potential\ energy

\frac{1}{2} (M+m).v^2=\frac{1}{2} k.x^2

\frac{1}{2} \times (2+0.01)\times 1.4925^2=\frac{1}{2} \times 19.6\times x^2

x=0.478\ m is the compression in the spring

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Answer:

a

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   B =  [\frac{\mu_o *  I }{ 2 \pi R^2} ]* r

Explanation:

From the question we are told that

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Ampere's law is mathematically represented as

       B[2 \pi r]  =  \mu_o  *  \frac{I r^2  }{R^2 }

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When r \ge R

=>     B =  \frac{ \mu_o *  I}{ 2 \pi r }

But when r< R

   B =  [\frac{\mu_o *  I }{ 2 \pi R^2} ]* r

     

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Answer:

They both are part of electromagnetic radiation.

Radio waves have longer wavelength than visible waves.

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A 40.0 kg beam is attached to a wall with a hi.nge and its far end is supported by a cable. The angle between the beam and the c
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The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.

To find the answer, we need to know about the tension.

<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
  • Let's draw the free body diagram of the system using the given data.
  • From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
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                           N_x=86.62N

  • We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.

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  • To find Ny, we need to find the tension T.
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  • Thus, the magnitude of the force that the beam exerts on the hi.nge will be,

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Thus, we can conclude that, the magnitude of the force that the beam exerts on the hi.nge is 261.12N.

Learn more about the tension here:

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